Given the reactant side of the total ionic equation for the neutralization reaction of lithium hydroxide (LiOH) with hydrochlori
c acid (HCl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow. Li+(aq)+OH−(aq)+H+(aq)+Cl−(aq)→
Be sure to include the charges on the ionic species and the physical state of all the reactant and product species.
<span>1) Combine the cation Li⁺ (aq) with the anion Cl- (aq) to form LiCl(s). </span> <span>LiCl is a solid soluble substance, a typical ionic compound. So, it will reamain as separate ions in the product side: Li⁺ + CL⁻</span>
<span>2) Combine the anion OH⁻ with the cation H⁺ to form H₂O(l). </span> <span>Since, the ionization of H₂O is low, it will remain as liquid in the product side: H₂O(l)</span>
<span>3) Finally, you can wirte the total ionic equation: </span> Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)
