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Kay [80]
3 years ago
11

Why should we follow school rules

Chemistry
2 answers:
WARRIOR [948]3 years ago
8 0
SIMPLIFIED: They are created to keep us safe so we wont do anything ridiculously stupid
slavikrds [6]3 years ago
3 0
Because the rules your school has is the things that will keep all of the students safe and... for the most part... happy and able to learn
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A sample of sugar (C12H22O11) contains
Mariana [72]

Answer:

0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N =  number of particles

Nᵃ = Avogadros constant = 6.02 x \\10^{23

So, n= \frac{1.505 X 10^{23} }{6.02 X 10^{23}}

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

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4 years ago
Wwicth substance makes a recipe unheatly
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If present in a high amount, unsaturated fat makes a substance an unhealthy choice in a recipe. 
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4 years ago
Pls help which law is that???
MAXImum [283]

Answer:

it is newtons third law

Explanation:

7 0
3 years ago
Read 2 more answers
The first strings of holiday lights were manufactured as series circuits. Which explains why this method is no longer used? A. I
user100 [1]
B because once the circuit is burned the lights will all go of
3 0
3 years ago
How many liters of hydrogen gas is produced from 3.712 g of magnesium with 104.2ml of 1.385 mol/L HCL (aq) at SATP? Please show
Licemer1 [7]

Answer:

V=1.61L

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Mg+2HCl\rightarrow MgCl_2+H_2

Next, we compute the reacting moles of each reactants:

n_{Mg}=3.712gMg*\frac{1molMg}{24.305 gMg}=0.153molMg

n_{HCl}=1.385\frac{molHCl}{L}*0.1042L=0.144molHCl

Then, as magnesium and hydrohloric acid are in a 1:2 molar ratio 0.153 moles of magnesium will completely react with 0.306 moles of hydrochloric acid yet we only have 0.144 moles, therefore, limiting reactant is hydrochloric acid. Thus, we compute the produced moles of hydrogen:

n_{H_2}=0.144molHCl*\frac{1molH_2}{2molHCl} =0.072molH_2

Finally, we use the ideal gas equation with T=298K and 1atm (STP conditions) to compute the liters of hydrogen gas:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{0.072mol*0.082\frac{atm*L}{mol*K}*273K}{1atm}\\  \\V=1.61L

Best regards.

3 0
3 years ago
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