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elena55 [62]
3 years ago
6

The first strings of holiday lights were manufactured as series circuits. Which explains why this method is no longer used? A. I

n order for a series circuit to remain closed, enabling electrons to flow, all lights must work. B. In a series circuit, if all lights work the circuit remains open, but if one burns, it closes the circuit. C. Lightbulb manufacturers stopped making lightbulbs that could be wired in series. D. Series circuits require more wire to keep electrons flowing between lightbulbs.
Chemistry
1 answer:
user100 [1]3 years ago
3 0
B because once the circuit is burned the lights will all go of
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Which compounds represent the
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Answer:

Both

compounds in left hand side of the equation is called reactants.

compounds in right hand side of the equation is called products.

so ans is both water and carbon di oxide

Explanation:

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2 years ago
the quantity of antimony in an ore can be determined by an oxidation-reduction titration with an oxidizing agent. The ore is dis
Basile [38]

Answer:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

Explanation:

At a redox equation, one substance is being oxidized (losing electrons), and the other is being reduced (gaining electrons). In the given reaction:

BrO₃⁻(aq) + Sb³⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq)

When it's at an acidic solution, it must be ions H⁺ on the reactant, which will form water with the oxygen, so the complete reaction is:

BrO₃⁻(aq) + Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + Sb⁵⁺(aq) + H₂O(l)

As we can see, the antimony is being oxidized (go from +3 to +5), and the Bromo is being reduced. The oxidation number of brome in the reactant, knowing that the oxidation number of O is -2, is:

x + 3*(-2) = -1

x = +5

So, it's going from +5 to -1, and the half-reactions are:

BrO₃⁻(aq) + 6e⁻ → Br⁻(aq)

Sb³⁺(aq) → Sb⁵⁺(aq) + 2e⁻

The number of electrons must be the same, so the second equation must be multiplied by 3:

3Sb³⁺(aq) → 3Sb⁵⁺(aq) + 6e⁻

Thus, the equation will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + H₂O(l)

Now, we verify the amount of the elements, which must be equal on both sides. So, we multiply H₂O by 3, and H⁺ by 6, and the balanced reaction will be:

BrO₃⁻(aq) + 3Sb³⁺(aq) + 6H⁺(aq) → Br⁻(aq) + 3Sb⁵⁺(aq) + 3H₂O(l)

6 0
3 years ago
Which mix will be homogeneous?
DIA [1.3K]

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B

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food coloring and water are inseparable after mixed.

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