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horsena [70]
3 years ago
9

What is the name of this hydrocarbon? 2-butane 2-butene 2-butyne 4-butyne 4-propyne

Chemistry
2 answers:
monitta3 years ago
5 0
2-butane is the correct answer
AlexFokin [52]3 years ago
4 0
Answer is 2- butyne
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Consider the following reaction at 298 K:
faltersainse [42]

Answer :

\Delta S_{sys} = -1622.8 J/K

\Delta S_{surr} = -94.6 J/K

\Delta S_{univ} = 0 J/K

Explanation :  Given,

\Delta H = -483.6 kJ

The given chemical reaction is:

2H_2(g)+O_2(g)\rightarrow 2H_2O(g)

First we have to calculate the value of \Delta S_{sys}.

\Delta S_{sys}=\frac{\Delta H}{T}

\Delta S_{sys}=\frac{-483.6kJ}{298K}

\Delta S_{sys}=-1.6228kJ/K=-1622.8J/K

Entropy of system = -1622.8 J/K

As we know that:

Entropy of system = -Entropy of surrounding = 1622.8 J/K

and,

Entropy of universe = Entropy of system + Entropy of surrounding

Entropy of universe = -1622.8 J/K + (1622.8 J/K)

Entropy of universe = 0

8 0
3 years ago
Give three examples of energy traveling in waves
mrs_skeptik [129]

Answer:

ELECTROMAGNETIC SPECTRUM. Radios, televisions, mobile phones, and radar use signals made up of electromagnetic waves. These are waves that carry energy as electricity and magnetism at the speed of light. Light we can see is also an electromagnetic wave, but other types of electromagnetic wave are invisible.

Explanation:

~Hope this helps

5 0
3 years ago
What differentiates one element from another
worty [1.4K]
I think the number of protons in the nucleus the number of valence electrons atomic mass... 
8 0
3 years ago
The fact that an organism cannot live without interacting with its surroundings is a concept in the field of study known as
ratelena [41]
Your answer is Echology. 
 
Definetion: Echology <span>is the </span>scientific<span> analysis and study of interactions among organisms and their environment. 

</span>
6 0
4 years ago
The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).
Rufina [12.5K]

Answer:

Mass = 182.4 g

Explanation:

Given data:

Number of moles of Al₂O₃ = 3.80 mol

Mass of oxygen required = ?

Solution:

Chemical equation:

4Al + 3O₂    →       2Al₂O₃

Now we will compare the moles of aluminum oxide and oxygen.

                Al₂O₃           :           O₂

                   2               :            3

                 3.80            :         3/2×3.80 = 5.7

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 5.7 mol × 32 g/mol

Mass = 182.4 g

4 0
3 years ago
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