All categories

3 years ago

What is the name of this hydrocarbon? 2-butane 2-butene 2-butyne 4-butyne 4-propyne

Chemistry

2 answers:

monitta3 years ago

5 0

2-butane is the correct answer

AlexFokin [52]3 years ago

4 0

Answer is 2- butyne

You might be interested in

Why is there not a constant molar volume for solids and

iragen [17]

Answer:

all of the above

Explanation:

i got the answer right on cK-12

7 0

3 years ago

What inner planet has enough gravity to hold on to all its gases

Viefleur [7K]

The earth has enough gravity to do that

3 0

3 years ago

Read 2 more answers

In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t

katrin2010 [14]

Answer: D) Eight

Just pretend this part doesn't exist nope nothing to see here the answer is correct on edge2020 I swear on my brainly points

4 0

3 years ago

Read 2 more answers

Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq

Inga [223]

Answer:

$M_{acid}=0.0444M$

Explanation:

Hello,

In this case, for the given reaction:

$H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4$

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

$2*n_{acid}=n_{base}$

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

$2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M$

Best regards.

5 0

3 years ago

In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i

fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2:</u> Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

7 0

3 years ago