Question

For which value of a are the graphs of –4 = 3x + 6y and ax – 8y = 12 parallel?

Answer 1

Answer:

The value of a is -4.

Step-by-step explanation:

Since, two lines $a_1 x+b_1 y=c_1$ and $a_2 x+b_2 y=c_2$ are called parallel lines,

If $\frac{a_1}{a_2}=\frac{b_1}{b_2}\neq \frac{c_1}{c_2}$

If 3x + 6y = 4 and ax-8y = 12 are parallel lines,

Then, by the above property,

$\frac{3}{a}=\frac{6}{-8}\neq \frac{4}{12}$

$\implies \frac{3}{a}=\frac{6}{-8}$

By cross multiplication,

$-24 = 6a$

$\implies -4=a$ ( Dividing both terms by 6}

Hence, the value of a is -4 for which 4 = 3x + 6y and ax – 8y = 12 are parallel.

Answer 2

Answer:

The answer is A) a=-4

Step-by-step explanation: