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Viktor [21]
3 years ago
6

Can someone please help me in physical science

Physics
1 answer:
Sonbull [250]3 years ago
7 0
Filling in a table with the changes and measured data values (c)
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An airplane is flying overhead at a constant elevation of 3000ft. A man is viewing the plane from a position 4000ft from the bas
ziro4ka [17]

Answer: The distance between the man and the plane increasing at a rate of 400ft/s

Explanation: Please see the attachments below

4 0
3 years ago
assuming birdman flies at height of 72m, how fast should he fly to hit bucket at 63m from start of field. gravity is -9.8m/s^2 n
algol [13]

Answer:

.....Birdman?

Explanation:

7 0
3 years ago
A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0
barxatty [35]

Answer:

Velocity = 3.25[m/s]

Explanation:

This problem can be solved if we use the Bernoulli equation: In the attached image we can see the conditions of the water inside the container.

In point 1, (surface of the water) we have the atmospheric pressure and at point 2 the water is coming out also at atmospheric pressure, therefore this members in the Bernoulli equation could be cancelled.

The velocity in the point 1 is zero because we have this conditional statement "The water surface drops very slowly and its speed is approximately zero"

h2 is located at point 2 and it will be zero.

(P_{1} +\frac{v_{1}^{2} }{2g} +h_{1} )=(P_{2} +\frac{v_{2}^{2} }{2g} +h_{2} )\\P_{1} =P_{2} \\v_{1}=0\\h_{2} =0\\v_{2}=\sqrt{0.54*9.81*2}\\v_{2}=3.25[m/s]

4 0
3 years ago
In order to do work, the force vector must be
gregori [183]

As we know that total work done by a force is given by

W = F.d

W = Fdcos\theta

so it is product of force and displacement along same direction

as we can write it as

W = (Fcos\theta)(d)

so it must be the product of force and displacement in same directions so correct answer must be

<u>B. in the same direction as the displacement vector and the motion.</u>

6 0
3 years ago
Read 2 more answers
If five joules were required to move a crate in 3.7 seconds, what power was applied?
AleksAgata [21]

Answer:

The answer to your question is 1.35 Watts

Explanation:

Data

Work = W = 5 J

time = t = 3.7 s

Power = P = ?

Formula

Power is a rate in which work is done or energy is transferred over time

P = \frac{W}{t}

Substitution

P = \frac{5}{3.7}

Result

P = 1.35 W

8 0
3 years ago
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