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vova2212 [387]
2 years ago
6

Marie is puzzled by her findings she has done several meticulous calculations and has gotten the numbers .37 rad, .89 rad and 1.

65 rad. she was expecting .90 rad each time. she has been which of the following?
a. neither precise and accurate
b. both precise and accurate
c. precise
d. accurate
Physics
1 answer:
Irina-Kira [14]2 years ago
6 0

Answer:

I think the answer is a

Explanation:

for it to be accurate has be to exactly 0.9 rad

it is not precise because the answer she is getting is different everytime and not even close. For instance,

It would have been precise if she had gotten 0.37 rad in every attempt. or 0.89 every attempt...

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Which provides the best analogy for an electron in an atomic orbital?
Svetllana [295]
<h2>Answer: a bee trying to escape from a closed jar  </h2>

In an atom the electrons will occupy orbitals so that their energy is as small as possible. That is why the orbitals are ordered based on their energy level in an increasing order, which is associated with a particular range of energy based on its distance from the atom nucleus.

In this sense, an electron "jumps" from one level to another in the atom in the same way a bee tries to escape from a closed jar.

3 0
2 years ago
single goose sounds a loud warning when an intruder enters the farmyard. Some distance from the goose, you measure the sound lev
Goryan [66]

Answer:

The sound level of the 26 geese is  Z_{26}= 96.15 dB

Explanation:

From the question we are told that

    The  sound level is Z_1 =  81.0 \ dB

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Generally the intensity level of sound is mathematically represented as

        The intensity of sound level in dB  for one  goose is mathematically represented as

                       Z_1 = 10 log [\frac{I}{I_O} ]

Where I_o is the  threshold level of intensity with value  I_o = 1*10^{-12} \  W/m^2

            I is the intensity for one goose in W/m^2

For 26 geese the intensity would be  

          I_{26} = 26 * I

   Then  the intensity of 26 geese in dB is  

              Z_{26} = 10 log[\frac{26 I }{I_o} ]

               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

               Z_{26} = 10 log (\ \ 26  \ \ ) *   (\ \  10 log [\frac{ I }{I_o} ]\ \ )

 From the law of logarithm we have that

              Z_{26} = 10 log 26 +  10 log [\frac{I}{I_0} ]

                    = 14.15 + 82

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4 0
3 years ago
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Hello,

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Explanation: Defense is to defend our team or group so that the other team or group does not win or take the ball from us or even advance the ball.

Hope this helped!

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7 0
2 years ago
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Answer:

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Answer:

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7 0
3 years ago
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