Using the scale model of the Sun given;
- The diameter of the Milky Way = 4.28 × 10¹¹ m
- The diameter of the Earth = 5.44 × 10⁻³ m
<h3>What is the diameter of the Milky Way?</h3>
The diameter of the Milky Way is about 1 × 10¹⁸ km.
The diameter of the Sun is about 1.4 × 10⁶ km
The diameter of the Earth is about 1.27 × 10⁴ km.
Using the scale model of the Sun given, the diameter of the Milky Way = (1 × 10¹⁸ km/1.4 × 10⁶ km) × 0.6 m
The diameter of the Milky Way = 4.28 × 10¹¹ m
Using the scale model of the Sun given, the diameter of the Milky Way = (1.27 × 10⁴ km/1.4 × 10⁶ km) × 0.6 m
The diameter of the Earth = 5.44 × 10⁻³ m
In conclusion, the diameter of the Milky Way is far bigger than the Sun while the diameter of the Sun is about 5400 times bigger than the Earth.
Learn more about the Milky Way, Sun, and Earth at: brainly.com/question/1995133
#SPJ1
Answer:
Explanation:
Let T be the tension in the string and mg is the weight of the block.
T = mg
By using Newton's second law
T - mg = ma
mg - mg = ma
a = 0
Thus, the acceleration is zero.
In order to make an electric current flow it is necessary to have a source of the current or source of free electrons and also the circuit should be a close one or complete. When there is a break in a circuit, no current would flow in the whole system.
Answer:
V (initial vertical velocity) = 45.4 sin 31.2 = 23.52 m/s
1/2 m V^2 = m g h conservation of energy
h = V^2 / (2 g) = 23.52^2 / 19.6 = 28.2 m max height
Check:
t = 28.2 / 9.8 = 2.88 sec time to reach max height
h = 23.52 * 2.88 - 1/2 g 2.88^2 = 27.1 m
