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Anuta_ua [19.1K]
3 years ago
9

What current in a solenoid 15-cm long wound with 100 turns would produce a magnetic field equal to that of the Earth, 5 cross ti

mes 10 to the power of negative 5 end exponentT ?
Physics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

The value is  I= 0.0597\  A  

Explanation:

From the question we are told that

    The length of the solenoid is l  =  15 \  cm  =  0.15 \  m

     The number of turns is  N  =  100

      The  magnetic field of the earth is  B  =  5* 10^{-5} \  T

Gnerally magnetic field is mathematically represented as

          B  =  \frac{\mu_o  *  N * I  }{ l }

=>        I= \frac{Bl}{ \mu_o *N  }

=>        I= \frac{ 5 *10^{-5} *  0.15}{4\pi *10^{-7} *100 }  

=>        I= 0.0597\  A  

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d=9.462×10^15 meters

Explanation:

<u>Relation between distance, temps and velocity:</u>

d=v*t

t=1year*(365days/1year)*/(24hours/1day)*(3600s/1h)=31536000s

So:

1 light year=d=3*10^8m/s*3.154*10^7s=9.462×10^15 meters

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3 years ago
A boxer can hit a heavy bag with great force. Why can't he hit a piece of tissue paper in midair with the same amount of force?
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Answer:

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Explanation:

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You can set these equal as mΔv = FΔt

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Answer:

The maximum pressure that will be attained in the tank before the plug melts and releases gas should be less than 74.26 atm.

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=49.2 atm\\T_1=39.0^oC = 312.15 K\\P_2=?\\T_2=198^oC=471.15 K

Putting values in above equation, we get:

\frac{49.2atm }{312.15 K}=\frac{P_2}{471.15 K}\\\\P_2=74.26 atm

The maximum pressure that will be attained in the tank before the plug melts and releases gas should be less than 74.26 atm.

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Answer:

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