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Anuta_ua [19.1K]
3 years ago
9

What current in a solenoid 15-cm long wound with 100 turns would produce a magnetic field equal to that of the Earth, 5 cross ti

mes 10 to the power of negative 5 end exponentT ?
Physics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

The value is  I= 0.0597\  A  

Explanation:

From the question we are told that

    The length of the solenoid is l  =  15 \  cm  =  0.15 \  m

     The number of turns is  N  =  100

      The  magnetic field of the earth is  B  =  5* 10^{-5} \  T

Gnerally magnetic field is mathematically represented as

          B  =  \frac{\mu_o  *  N * I  }{ l }

=>        I= \frac{Bl}{ \mu_o *N  }

=>        I= \frac{ 5 *10^{-5} *  0.15}{4\pi *10^{-7} *100 }  

=>        I= 0.0597\  A  

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How are particles in liquids, solids, and gases the same? How are they different?
Cerrena [4.2K]

Answer:

Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

Explanation:

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4 0
2 years ago
Which are base units used in the metric system? Check all that apply.
Shtirlitz [24]

Liters

Grams

Degrees Celsius

The other answer choices are from the imperial system

7 0
3 years ago
Read 2 more answers
What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?
konstantin123 [22]

Answer:

I=2.71\times 10^{-5}\ A

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.  

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}, r is radius

Let I is the displacement current. It is given by :

I=C\dfrac{dV}{dt}

Here, \dfrac{dV}{dt} is rate of increasing potential difference

So

I=\dfrac{\pi r^2\epsilon_o}{d}\times \dfrac{dV}{dt}\\\\I=\dfrac{\pi (0.03)^2\times 8.85\times 10^{-12}}{0.46\times 10^{-3}}\times 500000\\\\I=2.71\times 10^{-5}\ A

So, the value of displacement current is 2.71\times 10^{-5}\ A.

4 0
3 years ago
At which of the following air temperatures will the
monitta

Answer:

The answer is: B. -487 ..............

3 0
3 years ago
A narrow beam of light from a laser travels through air (n = 1.00) and strikes the surface of the water (n = 1.33) in a lake at
Natalka [10]

Answer:

A) d = 11.8m

B) d = 4.293 m

Explanation:

A) We are told that the angle of incidence;θ_i = 70°.

Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;

tan 70° = d/4.3m

Where d is the distance from point B at which the laser beam would strike the lakebottom.

So,d = 4.3*tan70

d = 11.8m

B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)

So,

n1*sinθ_i = n2*sinθ_r

Thus; sinθ_r = (n1*sinθ_i)/n2

sinθ_r = (1 * sin70)/1.33

sinθ_r = 0.7065

θ_r = sin^(-1)0.7065

θ_r = 44.95°

Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;

d = 4.3 tan44.95

d = 4.293 m

4 0
3 years ago
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