Question

What current in a solenoid 15-cm long wound with 100 turns would produce a magnetic field equal to that of the Earth, 5 cross times 10 to the power of negative 5 end exponentT ?

Answer 1

Answer:

The value is  $I= 0.0597\ A$  

Explanation:

From the question we are told that

    The length of the solenoid is $l = 15 \ cm = 0.15 \ m$

     The number of turns is  $N = 100$

      The  magnetic field of the earth is  $B = 5* 10^{-5} \ T$

Gnerally magnetic field is mathematically represented as

          $B = \frac{\mu_o * N * I }{ l }$

=>        $I= \frac{Bl}{ \mu_o *N }$

=>        $I= \frac{ 5 *10^{-5} * 0.15}{4\pi *10^{-7} *100 }$  

=>        $I= 0.0597\ A$