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BabaBlast [244]
3 years ago
15

Which of the following equations are correctly balanced?

Chemistry
2 answers:
lord [1]3 years ago
5 0
<span>The option IV is the correct answer and it has been balanced correctly.
</span><span>IV. 2 C3H6 + 9 O2 6 CO2 + 6 H2O</span>
kykrilka [37]3 years ago
3 0
Equations 2 and 4 are properly balanced
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Express 749 000 000 in scientific notation,
Dima020 [189]

Answer:

7.49 × 108

Explanation:

Scientific notation is a way to express numbers in a form that makes numbers that are too small or too large more convenient to write. It is commonly used in mathematics, engineering, and science, as it can help simplify arithmetic operations. In scientific notation, numbers are written as a base, b, referred to as the significant, multiplied by 10 raised to an integer exponent, n, which is referred to as the order of magnitude:

8 0
3 years ago
When balancing a chemical equation, the number of h atoms in 2 ch4 is eight?
Viktor [21]
Yes... that is correct.

CH4 is methane so the coefficent in front of it would double the number of atoms of each element
6 0
3 years ago
Calculate the volume of this irregular solid to the nearest cubic centimeter​
EleoNora [17]

Answer:

8 cm3

Explanation:

The volume of this irregular solid will calculated as the difference between the final volume and the initial volume;

The final volume of the water and the solid is 25 ml

The initial volume of the water alone was 17 ml

The volume of the irregular solid is thus approximately;

25 - 17 = 8 ml

We then use the conversion;

1 cm3 = 1 mL

Thus the volume of the solid is 8 cm3

6 0
3 years ago
Read 2 more answers
PLEASE HELP
Art [367]
1)water has a great capacity to hold a moderate heat energy
3 0
2 years ago
How many milliliters of a 5.0 M H2SO4 stock solution would you need to prepare 108.0 mL of 0.45 M H2SO4?
PIT_PIT [208]
For the purpose we will use solution dilution equation:
c1xV1=c2xV2
Where, c1 - concentration of stock solution; V1 - a volume of stock solution needed to make the new solution; c2 - final concentration of new solution; V2 - final volume of new solution.
c1 = 5.00 M
c2 = 0.45 M
V1 = ?
V2 = 108 L
When we plug values into the equation, we get following:
5 x V1 = 0.45 x 108
<span>V1 = </span>9.72 L
7 0
3 years ago
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