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3 years ago

The phase that is most likely to occur at high temperatures and high pressures is:

Chemistry

1 answer:

kogti [31]3 years ago

6 0

WELL IT DEPENDS ON WHAT IT DOING IT TO BUT TRY SOLID

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As the voltage across a resistor is increased, what happens to the resistance of the resistor?

vampirchik [111]

<h3>HELLO THERE, I HOPE MY ANSWER WILL HELP YOU :)</h3>

<h2>ANSWER-</h2>

-We will be paying close attention to the Ohm’s Law here:-

>Ohm's law states that the electrical current (I) flowing in an circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). >Therefore, if the voltage is increased, the current will increase provided the resistance of the circuit does not change.

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3 years ago

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. Consider the following 3 systems: a. A binary mixture with vapor-liquid equilibrium, both components are generally present in

Leona [35]

Offf kfff offf please thank me

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3 years ago

How is a heterogeneous mixture different from a homogeneous mixture?

MArishka [77]

A homogeneous mixture<span> has the same uniform appearance and composition throughout. Many </span>homogeneous mixtures<span> are commonly referred to as solutions. A </span>heterogeneous mixture <span>consists of visibly </span>different<span> substances or phases. The three phases or states of matter are gas, liquid, and solid. Now this is my answer. So revise it a little. You dont want plagiarism </span>

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4 years ago

When backpacking in the wilderness, hikers often boil water to sterilize it for drinking. Suppose that you are planning a backpa

Pavlova-9 [17]

Answer:

2.104 L fuel

Explanation:

Given that:

Volume of water = 35 L = 35 × 10³ mL

initial temperature of water = 25.0 ° C

The amount of heat needed to boil water at this temperature can be calculated by using the formula:

$q_{boiling} = mc \Delta T$

where

specific heat of water c= 4.18 J/g° C

$q_{boiling} = 35 \times 10^{3} \times \dfrac{1.00 \ g}{1 \ mL} \times 4.18 \ J/g^0 C \times (100 - 25)^0 C$

$q_{boiling} = 10.9725 \times 10^6 \ J$

Also; Assume that the fuel has an average formula of C7 H16 and 15% of the heat generated from combustion goes to heat the water;

thus the heat of combustion can be determined via the expression

$q_{combustion} =- \dfrac{q_{boiling}}{0.15}$

$q_{combustion} =- \dfrac{10.9725 \times 10^6 J}{0.15}$

$q_{combustion} = -7.315 \times 10^{7} \ J$

$q_{combustion} = -7.315 \times 10^{4} \ kJ$

For heptane; the equation for its combustion reaction can be written as:

$C_7H_{16} + 11O_{2(g)} -----> 7CO_{2(g)}+ 8H_2O_{(g)}$

The standard enthalpies of the products and the reactants are:

$\Delta H _f \ CO_{2(g)} = -393.5 kJ/mol$

$\Delta H _f \ H_2O_{(g)} = -242 kJ/mol$

$\Delta H _f \ C_7H_{16 }_{(g)} = -224.4 kJ/mol$

$\Delta H _f \ O_{2{(g)}} = 0 kJ/mol$

Therefore; the standard enthalpy for this combustion reaction is:

$\Delta H ^0= \sum n_p\Delta H^0_{f(products)}- \sum n_r\Delta H^0_{f(reactants)}$

$\Delta H^0 =( 7 \ mol ( -393.5 \ kJ/mol) + 8 \ mol (-242 \ kJ/mol) -1 \ mol( -224.4 \ kJ/mol) - 11 \ mol (0 \ kJ/mol))$

$\Delta H^0 = (-2754.5 \ \ kJ - 1936 \ \ kJ+224.4 \ \ kJ+0 \ \ kJ)$

$\Delta H^0 = -4466.1 \ kJ$

This simply implies that the amount of heat released from 1 mol of C7H16 = 4466.1 kJ

However the number of moles of fuel required to burn $7.315 \times 10^{4} \ kJ$ heat released is:

$n_{fuel} = \dfrac{q}{\Delta \ H^0}$

$n_{fuel} = \dfrac{-7.315 \times 10^{4} \ kJ}{-4466.1 \ kJ}$

$n_{fuel} = 16.38 \ mol \ of \ C_7 H_{16$

Since number of moles = mass/molar mass

The mass of the fuel is:

$m_{fuel } = 16.38 mol \times 100.198 \ g/mol}$

$m_{fuel } = 1.641 \times 10^{3} \ g$

Given that the density of the fuel is = 0.78 g/mL

and we know that :

density = mass/volume

therefore making volume the subject of the formula in order to determine the volume of the fuel ; we have

volume of the fuel = mass of the fuel / density of the fuel

volume of the fuel = $\dfrac{1.641 \times 10^3 \ g }{0.78 g/mL} \times \dfrac{L}{10^3 \ mL}$

volume of the fuel = 2.104 L fuel

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4 years ago

renata developed a hair dye additive that is guaranteed to cover grey hair. she granted the right to use this additive to a majo

kvasek [131]

What Renata has granted to the manufacturer of the colored hair dye is called a patent.

<h3>What is a patent?</h3>

A patent is a right given to a manufacturer to be the sole producer of a product for a given period of time. Usually, the patent has to last for a given number of years after which the technology becomes commonplace.

Hence, what Renata has granted to the manufacturer of the colored hair dye is called a patent.

Learn more about patent:brainly.com/question/12882864?r

#SPJ1

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2 years ago