A 3 L pocket of air at sea level has a pressure of 100 atm. Suppose the air pockets rise in the atmosphere to a certain height a nd expands to a volume of 10 L. What is the pressure of the air at the new volume?
1 answer:
Answer:
30 atm
Explanation:
Initial Volume, V1 = 3L
Initial Pressure, P1 = 100 atm
Final Volume V2 = 10 L
Final Pressure, P2 = ?
These quantities are related by the Boyle's law equation which is given as;
V1P1 = V2P2
P2 = V1 * P1 / V2
P2 = 3 * 100 / 10
P2 = 30 atm
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