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Westkost [7]
2 years ago
10

A 3 L pocket of air at sea level has a pressure of 100 atm. Suppose the air pockets rise in the atmosphere to a certain height a

nd expands to a volume of 10 L. What is the pressure of the air at the new volume?
Chemistry
1 answer:
liraira [26]2 years ago
5 0

Answer:

30 atm

Explanation:

Initial Volume, V1 = 3L

Initial Pressure, P1 = 100 atm

Final Volume V2 = 10 L

Final Pressure, P2 = ?

These quantities are related by the Boyle's law equation which is given as;

V1P1 = V2P2

P2 = V1 * P1  /  V2

P2 = 3 * 100 / 10

P2 = 30 atm

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To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance.
kap26 [50]

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

In spectrophotometry, to plot the calibration curve, you need to prepare solutions with known concentrations and measure their absorbance.

We have a standard iron solution with a concentration of 0.2500g/L of pure iron (C₁). We pipet 25.00mL (V₁) of this standard iron solution into a 500mL (V₂) volumetric flask and dilute up to the mark with distilled water.

We can calculate the concentration of the diluted solution (C₂) using the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\\\C_2 = \frac{C_1 \times V_1}{V_2}  = \frac{0.2500 g/L \times 25.00 mL}{500 mL} = 0.0125 g/L

Then, if we wanted to prepare the blank, that is, the solution that contains the same matrix but not the analyte, and whose concentration in iron is 0.00 mg/L, we wouldn't pipet any of the diluted solution.

To plot the calibration curve, you need to prepare iron solutions with known concentrations and measure their absorbance. You need to pipet 0 mL of the diluted solution to have 0.00 mg of iron.

Learn  more: brainly.com/question/24195565

8 0
2 years ago
Question 4 options: what is the volume of 1.2 moles of water vapor at stp?
Law Incorporation [45]
What is the volume of 1.2 moles of water vapor at STP?
The answer is 26.9
3 0
3 years ago
3. Given the following equation:
miskamm [114]

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

Mass of one atom/mole of potassium is 39.098 grams

Number of moles is 2.5 grams = \frac{2.5}{39.098} = 0.064

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

Mass of one molecule of KCl is 74.5513 g/mol

Mass of 0.064 moles of KCl is 4.767 grams

4 0
2 years ago
The boiling point of an aqueous solution is 102.08 °C. What is the freezing point? Constants can be found here.
enyata [817]

Colligative properties calculations are used for this type of problem. Calculations are as follows:<span>


ΔT(freezing point)  = (Kf)(molality)
ΔT(freezing point)  = 1.86 °C kg / mol (molality)
 </span>Tf - 102.08 = 1.86m

Tf = 1.86m + 102.08

The concetration of the solution is needed in order to obtain a specific value.

7 0
3 years ago
The "Atomic Number" is another way to refer to: a the number of atomic mass units b the number of neutrons c the number of elect
serious [3.7K]

Answer:

D. The number of protons.

4 0
3 years ago
Read 2 more answers
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