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alina1380 [7]
3 years ago
5

A calorimeter contains 124 g of water at 26.6°C. A block of metal with a mass of 26 g is heated to 95.8°C and then placed in the

water in the calorimeter. After sufficient time, the temperature of the water is measured and found to be 29.0°C. Calculate the heat capacity per gram of metal. Assume no heat is lost to the calorimeter or the surroundings.
Chemistry
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

The heat capacity of the metal is 0.717 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of water = 124.0 grams

Mass of metal = 26.0 grams

Temperature of water = 26.6 °C

Temperature of metal = 95.8 °C

Final temperature of the water = 29.0 °C

<u>Step 2</u>: Calculate heat capacity of metal

Qlost = -Q gained

Qmetal = -Qwater

Q = m*c*ΔT

⇒ with m = mass in grams

⇒ c= the heat capacity in J/g°C

⇒ ΔT = The change in temperature = T2 - T1 (in °C)

Qmetal = -Qwater

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

26 *c(metal) *(29-95.8) = -124 * 4.184 *(29-26.6)

-1736.8 * c(metal) = -1245.16

c(metal) = 0.717 J/g°C

The heat capacity of the metal is 0.717 J/g°C

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