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pickupchik [31]
3 years ago
6

A student needs to prepare 50.0 mL of 0.80 M aqueous H2O2 solution. Calculate the volume of 4.6 M H2O2 stock solution that shoul

d be used.
Chemistry
1 answer:
Degger [83]3 years ago
7 0

Answer:

We need 8.7 mL of the stock solution

Explanation:

Step 1: Data given

Volume of the solution he wants to prepare = 50.0 mL = 0.050 L

Concentration of the solution he wants to prepare = 0.80 M

The concentration of the stock solution = 4.6 M

Step 2: Calculate the volume of the stock solution

C1*V1 = C2*V2

⇒with C1 = the concentration of the stock solution = 4.6 M

⇒with V1 = the volume of the stock solution = TO BE DETERMINED

⇒with C2 = the concentration of the prepared solution = 0.80 M

⇒with V2 = the volume of the prepared solution = 0.050 L

4.6 M * V2 = 0.80 M * 0.050 L

V2 = (0.80 M * 0.050 L) / 4.6M

V2 = 0.0087 L = 8.7 mL

We need 8.7 mL of the stock solution

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Answer:

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Explanation:

Data obtained from the question include:

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Answer:

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⇒  P₂ = [(768 torr) × (8.00 m³)] ÷ (16.80 m³)

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