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Nana76 [90]
3 years ago
12

What is the final temperature when 125 g of H20 at 16°C is mixed with 185 g of H20 at 82°C?

Chemistry
1 answer:
dangina [55]3 years ago
6 0

Answer:

english

Explanation:

98

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Potassium hydroxide, KOH, is considered a _____________ in an acid-base reaction because it ___________ a hydrogen ion to/from t
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<span>Answer: Potassium hydroxide, KOH, is considered a BASE in an acid-base reaction because it ACCEPTS a hydrogen ion from the other reactant.

According to </span><span>Brønsted–Lowry acid–base theory, Base is a specie which accepts proton (H</span>⁺) while, Acid is a specie which donate proton.

Bases may contain a negative charge or lone pair of electrons, while, Acids contain positive charge or a neutral atom with incomplete octet.

In given statement KOH is acting as a base because it contains a negatively charged hydroxyl group which can accept proton from a acid, i.e. 

                                    KOH    →     K⁺  +  OH⁻

Reaction of OH⁻ with any acid,

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Blood is considered the river of life. do you agree?
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Answer:

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6 0
3 years ago
I need help ASAP please
Andrej [43]

525L

Explanation:

Given parameters:

Volume to Temperature ratio = 1.75

Temperature = 300k

Unknown:

Volume of the gas = ?

Solution:

We must carefully analyze and comprehend the detailed description of this experiment:

 It was suggest that the gas could expand or shrink without changing the pressure of the gas inside.

This implies that the pressure in the vessel is constant

This similar to the postulate of the Charles's law: The volume of a fixed mass of gas is directly proportional to the absolute temperature if the pressure is constant.

 Mathematically;

                 \frac{V1}{T1}  = \frac{V2}{T2}

V and T are the volume and temperature

 Now we can solve the given problem;

           \frac{V}{T}  = 1.75

Since temperature is given as 300K

 Input the variables:

           \frac{V}{300}  =  1.75

          V = 1.75 x 300 = 525L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

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