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Levart [38]
3 years ago
13

Please fast I need you to do this question FOR 15POINTS!!!!!!

Chemistry
2 answers:
erik [133]3 years ago
8 0
I answered this, have a look at your other post :)
sergeinik [125]3 years ago
4 0
Ok I’m figuring this one out
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If you had an aqueous mixture that contained Ag+ , K+ , and Pb2+ cations, how many different solids could precipitate if a chlor
SCORPION-xisa [38]

Answer:

Two, KCl and PbCl₂.

Explanation:

Hello!

In this case, since the addition of chloride ions promote the following three ionic reactions:

Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)\\\\K^+(aq)+Cl^-(aq)\rightleftharpoons KCl(aq)\\\\Pb^{2+}(aq)+Cl^-(aq)\rightleftharpoons PbCl_2(s)

We can infer that both silver chloride and lead (II) chloride are precipitated products as their Ksp are 6.56x10⁻⁴ and 1.59x10⁻⁵ respectively, which means they are merely soluble in water.

Best regards!

3 0
3 years ago
Changes between a liquid and gas exsample​
exis [7]

Here are some examples:-

Water → water vapour

bromine →  bromine gas

6 0
2 years ago
Calculate the volume of the gas, in liters, if 1.75 mol has a pressure of 1.28 atm at a temperature of -7 ∘C
Alexandra [31]

Answer:

A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.

 

You need to apply the ideal gas law PV=nRT

 

You have the pressure, P=1.01 atm

you have the volume, V = 2.21 L

The ideal gas constant R= 0.08205 L. atm/ mole.K at  273 K

 

find n = PV/RT = (1.01 atm x 2.21 L / 0.08205 L.atm/ mole.K x 273 K)

 

n= 0.1 mole, Now find the pressure for n=0.1 mole, T= 299K and

L=1.23 L

 

P=nRT/V= 0.1mole x 0.08205 (L.atm/ mole.K x 299 k)/ 1.23 L

= 1.994 atm

Explanation:

6 0
2 years ago
What is the Mass in grams of 3.1 mol of mercury
nasty-shy [4]
Answer: 200.59 grams
6 0
3 years ago
A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density? Answer in g/mL.
solong [7]

Answer:

The answer is

<h2>2.7 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of aluminum = 40.5 g

volume = 15 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{40.5}{15}

We have the final answer as

<h3>2.7 g/mL</h3>

Hope this helps you

8 0
3 years ago
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