Need some help with this question.
1 answer:
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The graph is missing, so i have attached it.
Answer:
From 0 hours to 2 hours.
Step-by-step explanation:
From the attached graph, we can see that on the y-axis, denotes the level of ibuprofen in the patient’s bloodstream while the x-axis denotes the amount of hours after the ibuprofen was taken.
Now, looking at the graph, we can see that the curve goes up from a time of 0 hours which corresponds to 0 mg of ibuprofen to a time of 2 hours which corresponds to 400 mg of ibuprofen.
After that point, the curve begins to to go down. Since we are concerned with increase, we will make do with the first statement.
Thus, we can say the period at which the level of ibuprofen increased was from 0 hours to 2 hours.
F(x) = 1/x is a special function. is called the multiplicative inverse or the reciprocal function. the specific shape of the graph is called a rectangular hyperbola.
negative values of x with produce negative values of f(x) and positive values will produce positive function values. so this hyperbola is symmetric with respect to the origin and all negative values are in Q3 and all positive values are in Q1.
as x gets farther and farther from 0 in either direction, you can see that 1/x will be an ever-increasingly smaller distance from the x-axis. indeed, the limit of this function is zero as x approaches either positive or negative infinity.
if x is between -1 and 1, then the value of f(x) increases until x = 0, the limit of the function as x approaches 0 being positive and negative infinity depending on which direction you are coming from.
the domain is all real numbers with the exception of 0
the range also happens to be all real numbers with the exception of zero. all that really means is that zero has no multiplicative inverse.
strictly speaking, this is an exponential function, as the function is f(x) = x^(-1).
negative values of x with produce negative values of f(x) and positive values will produce positive function values. so this hyperbola is symmetric with respect to the origin and all negative values are in Q3 and all positive values are in Q1.
as x gets farther and farther from 0 in either direction, you can see that 1/x will be an ever-increasingly smaller distance from the x-axis. indeed, the limit of this function is zero as x approaches either positive or negative infinity.
if x is between -1 and 1, then the value of f(x) increases until x = 0, the limit of the function as x approaches 0 being positive and negative infinity depending on which direction you are coming from.
the domain is all real numbers with the exception of 0
the range also happens to be all real numbers with the exception of zero. all that really means is that zero has no multiplicative inverse.
strictly speaking, this is an exponential function, as the function is f(x) = x^(-1).