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tatuchka [14]
3 years ago
13

Please help me and pls explain me how u got the answer

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
7 0

Answer: 8.55x10^13

Step-by-step explanation: 1.9 x 4.5 = 8.55  10^10 + 10^3 = 10^13

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Please answer the two questions.
Anarel [89]

Answer:

1. n= 14

2. n=3

Step-by-step explanation:

For the first problem, let's break down the equation. The number being thought about can be represented by <em>n</em>. Then <em>n </em>is increased by 7, or simply put 7+ <em>n. </em>The sum is 21, so to find n you can use the equation 7 + n = 24 and solve for <em>n, </em>which is 14.

For problem two, the same strategy can be used. The number is <em>n, </em>multiplied by 9. So, 9 * <em>n</em> is equal to 27. Solve for n by isolating n, and the answer is 3.

6 0
3 years ago
Read 2 more answers
I need the answer to this.
anastassius [24]

Hey there!

4/3 ÷ -24

= 4/3 ÷ -24/1

= 4/3 ÷ 1/-24

= 4(1) / 3(-24)

= 4 / -72

= 4 ÷ 4 / -72 ÷ 4

= - 1 / 18

≈ -0.055556

Therefore, your answer is: -1/18

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0
2 years ago
Read 2 more answers
Round to the nearest tenth place it is repeating decimal 4/6
Scilla [17]

Answer:

0.7

Step-by-step explanation:

I divided 4 by 6

0.6666666666666...

Simplify to 0.7

8 0
4 years ago
Please help me ! Today 11/6/2020 :(
dangina [55]
I believe the answer is c, TSR
5 0
3 years ago
During the exponential phase, E. coli bacteria in a culture increase in number at a rate proportional to the current population.
NikAS [45]

Answer:

  197.2 million

Step-by-step explanation:

The appropriate exponential equation for the population is ...

  p(t) = 172.0e^(0.019t)

Then we can compute for t=7.2:

  p(7.2) = 172.0e^(0.019·7.2) ≈ 172.0·1.146599 ≈ 197.2

7.2 minutes from now, the population will be about 197.2 million.

___

For continuous growth (or continuous compounding), the exponential formula is ...

  f(t) = (value at t=0)×e^(rt)

where r is the growth rate in one unit of time, and t is the number of time periods.

8 0
3 years ago
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