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Evgesh-ka [11]
3 years ago
7

Can someone get my schoolwork to 15% done

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

whats the login :)

Step-by-step explanation:

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-3/8 divided -1/4 what is the quotient ?
sweet [91]

Answer:

the answer is 12/8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1.Which are the equation and solution for the sentence, "Anumber, n, divided by
Assoli18 [71]

Answer:

1) B/ 0.4n = 12; n = 30

2) B/ 125 – x = 58

3) B/ $1.75

Step-by-step explanation:

1) 0.4n = 12

n = 12 ÷ 0.4

n = 30

2) 125 – x = 58

– x = 58 – 125

– x = – 67 ( – & – will get cancelled)

x = 67

a) 125 + x = 58

x = 58 – 125

x = – 67 (pages won't be in negative)

c) 125 ÷ 58 = x

2.15 = x (wrong)

d) 58 – x = 125

– x = 125 – 58

– x = 67

x = 67 ÷ –1

x = – 67 ( pages won't be in negative)

3) 12x = 21

x = 21 ÷ 12

x = 1.75

3 0
3 years ago
The faces of a die are labelled 1,2,2,3,4,5. The die is rolled 200 times. How many times would you expect the number 2 to appear
DIA [1.3K]
2 out of 6 times or 1 out of 3 times.  It is most likely to land on a 2 than the other numbers.
3 0
3 years ago
Adam’s sister wants to watch her intake of fat per day.
Paladinen [302]
48/70 = 24/35 

24/35 = 0.6857

= 68.57%
5 0
4 years ago
Read 2 more answers
What is the product of the two matrices? Fill in the missing elements of the resulting matrix.​
olganol [36]

The product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Here we are given the 2 matrices as follows-

\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]

= \left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]

= \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Thus, the product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Learn more about matrices here-

brainly.com/question/13595915

#SPJ1

3 0
1 year ago
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