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ella [17]
3 years ago
8

A cylindrical cable of radius 8.57 mm carries a current of 25.5 a, uniformly spread over its cross-sectional area. at what dista

nce from the center of the wire is there a point within the wire where the magnetic field is 0.447 mt?
Physics
1 answer:
notsponge [240]3 years ago
5 0
I think there is a problem with this question because the answer is not inside the wire as stated, but would require a bigger wire than stated. This should be a standard ampere's law problem, B = I(mu), where B is the magnetic field, I is the current and mu is the magnetic permitivity constant (4*pi * 10^-7 H/m or T/A). We can describe the amount of current we get from our distance from the center of the wire with a ratio of areas (pi*r^2/pi*d^2), where r is our particular distance from the center (what we're trying to find) and d is the total radius of the wire. Adding this into ampere's law and canceling the pi's we get B = I*(mu)*(r^2/d^2), solving for r we get r = sqrt(B*d^2/(I*(mu))), when you plug values in, it gives an r of 32mm, which is much bigger than the actual radius of the wire. Maybe something was copied wrong?
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Compare and contrast electric conductors and electric insulators. Give an example of each.
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3 0
3 years ago
The MAC is 58 inches, The CG limits are from 26% to 43% MAC. If the CG is found to be
eimsori [14]

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

<h3>What are the limits?</h3>

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

  • 26% → (26%/100%)*58in = 0.26*58 in = 15.08 in
  • 43% → (43%/100%)*58in = 0.43*58 in = 24.94 in.

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

If you want to learn more about percentages, you can read:

brainly.com/question/14345924

6 0
2 years ago
A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of
anyanavicka [17]

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Mathematical models are representations of real situations. Models often serve the purpose of prediction and can help to explain and simplify certain mathematical problems.

The model; f(x) = 300x + 1,000 represents the number of additional square feet that can be paved in an hour after 1,000 square feet has already been paved.

From the above we can see that the correct answer is; "900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount."

Learn more: brainly.com/question/731147

6 0
3 years ago
Using a force of 28.0 Newton, a student pulls a 70.0 Newton weight along the tabletop for a distance of 15.0 meters in 3.0 secon
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Answer:

140 watt

Explanation:

We are given that

Force applied by student ,F=28 N

Weight pulled  by students=70 N

Displacement,s=15 m

Time=3 s

We have to find the power developed  by the student.

Work done=w=F\times s

Work done by the student=28\times 15=420 J

Power=\frac{work\;done}{time}

Using the formula

Power=\frac{420}{3}=140watt

Hence, the power developed by the students=140 watt

8 0
3 years ago
What is the speed of the sun as it orbits the center of the galaxy ?
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800,000 km/hr is the answr
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