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ella [17]
3 years ago
8

A cylindrical cable of radius 8.57 mm carries a current of 25.5 a, uniformly spread over its cross-sectional area. at what dista

nce from the center of the wire is there a point within the wire where the magnetic field is 0.447 mt?
Physics
1 answer:
notsponge [240]3 years ago
5 0
I think there is a problem with this question because the answer is not inside the wire as stated, but would require a bigger wire than stated. This should be a standard ampere's law problem, B = I(mu), where B is the magnetic field, I is the current and mu is the magnetic permitivity constant (4*pi * 10^-7 H/m or T/A). We can describe the amount of current we get from our distance from the center of the wire with a ratio of areas (pi*r^2/pi*d^2), where r is our particular distance from the center (what we're trying to find) and d is the total radius of the wire. Adding this into ampere's law and canceling the pi's we get B = I*(mu)*(r^2/d^2), solving for r we get r = sqrt(B*d^2/(I*(mu))), when you plug values in, it gives an r of 32mm, which is much bigger than the actual radius of the wire. Maybe something was copied wrong?
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What are some indicators that a chemical reaction is occurring? Check all that apply.
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The formation of bubbles, a change in color, and the formation of a precipitate (1, 3, & 5) are all indicators that a chemical reaction is occurring.

6 0
3 years ago
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In a diffraction grating experiment, light of 600 nm wavelength produces a first-order maximum 0.350 mm from the central maximum
NARA [144]

Answer:

497.143 nm.

Explanation:

Diffraction grating experiment is actually done by passing light through diffraction glasses, the passage of the light causes some patterns which can be seen on the screen. This is because light is a wave and it can spread.

The solution to the question is through the use of the formula in the equation (1) below;

Sin θ = m × λ. ---------------------------------(1).

Where m takes values from 0, 1, 2, ...(that is the diffraction grating principal maxima).

Also, m × λ = dc/ B -------------------------------------------(2).

We are to find the second wavelength, therefore;

λ2 =( m1/c1) × (c2/m2) × λ1 ------------------------(3).

Where c1 and c2 are the order maximum and m = order numbers. Hence;

λ2 = (1/ .350) × (.870/3) × 600 = 497.143 nm.

7 0
3 years ago
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An automobile traveling 50km/hr. It decelerates at 5 meter per second square. How long will it take to stop the car? How far wil
const2013 [10]
We know, a = v/t
Here, a = 5 m/s²
v = 50 km/h= 13.88 m/s

Substitute their values into the expression:
5 = 13.88 / t
t = 13.88/5
t = 2.78 sec

Now, we know, v = d/t
13.88 = d/2.78
d = 13.88 * 2.78
d = 38.53 meter

In short, Your Answers would be:
i) It will take 2.78 sec
ii) It will travel for 38.53 m after a brakes applied.

Hope this helps!
3 0
3 years ago
A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t
Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

y=\frac{1}{2}at^2

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s

10.87 seconds

F) The velocity just before the rocket arrives to the ground is:

v=\sqrt{2gy}=\sqrt{2(9.8m/s ^2)(580m)}=106.62\frac{m}{s}

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3 years ago
When working with electric charges, what symbol is used in equations to represent the electric field of an object?
Rus_ich [418]

E= electric field

E=F/q= force per unit charge

q= charge

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3 years ago
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