Explanation:
The given data is as follows.
height (h) = 98.0 m, speed (v) = 73.0 m/s,
Formula of height in vertical direction is as follows.
h = 
,
or, t = 
Now, formula for the required distance (d) is as follows.
d = vt
= 
= 
= 326.5 m
Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.
E = 1/2 m v^2
108000m /3600 = 30m/s
E = 1525 * 0.5 * 30 = 22875 J
<u>We are given:</u>
Initial velocity (u) = 32 m/s
Acceleration (a) = 3 m/s²
Displacement (s) = 40 m
Final Velocity (v) = v m/s
<u>Solving for the Final Velocity:</u>
from the third equation of motion:
v² - u² = 2as
<em>replacing the variables</em>
v² - (32)² = 2(3)(40)
v² = 240 + 1024
v² = 1264
v = √1264
v = 35.5 m/s
Therefore, the velocity of the bike after travelling 40 m is 35.5 m/s
Answer:
i think number 4 :/ i hope its right...
Use F=ma formula
F=m v/t. a=v/t
put values u will get answer.
answer should be around 30N .
