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vazorg [7]
2 years ago
5

5/2x5/3x5/4 Solve for the volume Please help

Mathematics
1 answer:
Arada [10]2 years ago
4 0

Answer:

ur a sixth grader do the spiral review dabs

Step-by-step explanation:

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Attached is what the graph should look like

Step-by-step explanation:

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2 years ago
The product of 2 more than 5 times a number and 4 less than three times a number
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Sorry I'm not sure if I'm right just my thinking...

set the number to be x so that (5x+2)(3x-4)??

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3 years ago
Find the equation of a line that passes through points (1,8) and (4,4).​
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2 years ago
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

8 0
3 years ago
HCF of the numbers divisible be<br> 3 between 21 and 30 is ___​
blsea [12.9K]

Answer:

3

Step-by-step explanation:

Numbers between 21 and 30 divisible by 3 are 24 and 27. so you get the HCF of the two.

3 0
3 years ago
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