Answer:
um... you are wrong
Step-by-step explanation:
its the the last one
you can't add when its division
you can change exponents from 1/x^-2
to x^2
<h2>
<em><u>I nweed brainliest</u></em></h2>
Step-by-step explanation:
2(3x + 5y = -19)
6x + 10y = -38
5 (5x -2y = 16)
25x - 10y = 80
19x = 42
but idk from there the rest doesn't work Soo if u can find the prob and tell me I'll fix it.
First write out all the two digit square numbers
4² = 16
5² = 25
6² = 36
7² = 49
8² = 64
9² = 81
Next divide all of them by 7
16/7 = 2 2/7 or 2 and 2 remainders
25/7 = 3 4/7 or 3 and 4 remainders
36/7 = 5 1/7 or 5 and 1 remainder
49/7 = 7
64/7 = 9 1/7 or 9 and 1 remainder
81/7 = 11 4/7 or 11 and 4 remainders
This tells us that the only possible remainders for a two digit square number divided by 7 are 1, 2 and 4
If Doris got 6 and Horace got 3, they must have made a mistake.
Answer:
4
Step-by-step explanation: you have t do y plus 10 and then add 4 minus -2