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ikadub [295]
3 years ago
11

Which set or sets does -24 belong? interger, rational, or whole number.

Mathematics
2 answers:
Snezhnost [94]3 years ago
4 0
Integers are
-4,-3,-2,-1,0,1,2,3,4...

-24 is an integer

ratinoal is numbers that can be written in a/b
-24=-24/1
it is a rational number

whole numbers are
0,1,2,3,4,5
no negatives
not a whole number



it is in integer and rational
olya-2409 [2.1K]3 years ago
3 0
-24 belongs to interger 
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1

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Step-by-step explanation:

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Find the area of a triangle with:
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Answer:

161cm2

Step-by-step explanation:

Area: 1/2 x base x height

1/2 x 14 x 23=161

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Hope this helps!

8 0
3 years ago
Rewrite 8x - 7 as the product of two factors
kykrilka [37]

Answer:

factors are any group of number or expressions which, when multiplied, produce another number or expression.

Basic example:  4 can be broken into 2 factors---2 and 2.  2 times 2 = 4

Example using an unknown:

2X + 6 = 2 * (X + 3)

In the given problem, there is no whole-number common factor.  A normal convention would be to factor based on the unknown term----thus 8X is factored into 8 and X.

So:  8X + 7 = 8 ( X + 7/8 )

The following would also be correct:

8X + 7 = 4 ( 2X + 7/4 )

Step-by-step explanation:

8 0
3 years ago
What is happening to this graph when the x-values are between 4 and 8?
Nikolay [14]

Answer: it remains constant

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3 0
3 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
2 years ago
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