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topjm [15]
3 years ago
10

javon is helping his dad build a tree house. he has a piece of trim that is 13 ft long. how many pieces can Javon cut that are 1

yard long? how much of a yard will he have left over?
Mathematics
2 answers:
frutty [35]3 years ago
8 0
You have one third of the yard left hope this helped you!
wel3 years ago
6 0
Well a yard is 3 ft
so  divide 3 into 13
3 goes into 13 4 times and you get 12
you have 4 whole yards and 1 ft left or 1/3 of a yard.
:) hoped this helped

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Jeff wants to use mental math to see if he can afford the computer and printer shown. First he makes a ten by adding 527+3. What
tatiyna

Answer:

Step-by-step explanation:

7 0
2 years ago
Can some one please help me with this im having trouble. ?
dlinn [17]
So 12=total
7=blue
black=total-blue=12-7=5
black=5

1. 2/3 of 12 were taken out or 24/3 were taken out or 8 marbles were taken out
   there is not enough info becasue it doesn't specify which ones were taken out

2. there is not enough info

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3 0
2 years ago
Select the three equations that are correct.
nika2105 [10]

Answer:

6 × 9 = 54

42 ÷ 7 = 6

56 ÷ 7 = 8

Step-by-step explanation:

Given:

6 × 9 = 54

8 × 4 = 34

42 ÷ 7 = 6

64 ÷ 9 = 7

56 ÷ 7 = 8

Now it need to verify,

6 × 9 = 54 this is correct

42 ÷ 7 = 6 This is also correct

56 ÷ 7 = 8 This is correct

3 0
2 years ago
Choose the solutions of the following systems of equations x^2+y^2=6 and x^2-y=6
den301095 [7]

Answer:

The solutions are (-√6,0) and (√6,0)

(-√5,-1) and (√5,-1)

Step-by-step explanation:

The equations are:

{x}^{2}  +  {y}^{2}  = 6

and

{x}^{2}  - y = 6

We make y the subject in the second equation to get;

y =  {x}^{2}  - 6

We substitute into the first equation to get:

{x}^{2}  +  ({x}^{2}  - 6 )^2= 6

x =  \pm \sqrt{6}

and x =  \pm \sqrt{5}

The solutions are (-√6,0) and (√6,0)

(-√5,-1) and (√5,-1)

7 0
2 years ago
Please help me solve this problem
Lera25 [3.4K]

Answer:

x ≤ 17

Step-by-step explanation:

This is the same as solving an equation, except instead of and equal sign it's an arrow.

We have to evaluate everything in the parenthesis first.

3x - 2 (x + 1) ≤ 15

3x - 2x - 2 ≤ 15

Next, we combine like terms - x's

3x - 2x - 2 ≤ 15

x - 2 ≤ 15

Combine like terms - constants (add 2 to both sides)

x - 2 ≤ 15

<u>x ≤ 17</u>

5 0
2 years ago
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