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Blizzard [7]
3 years ago
13

I NEED HELP PLEASE ITS DUE SOOM

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.

Edit: Explanation

The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.

In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)

In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)

To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.

8° / 2 = 4° per hour for 4-6 PM

9° / 4 = 2.25° per hour from 6-10 PM

Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.

yarga [219]3 years ago
6 0

Answer:

i agree with Mai because she/he (im not really sure) said that the temperature changed quicker in the time between 6 and 10 pm. the temperature change was 9 in those 4 hours.

Step-by-step explanation:

well there's a 4 hour difference between all 3 of the times

4 pm - 6pm

25 - 17 = 8

8 degree difference

6 pm - 10 pm

17 - 8 = 9

9 degree difference

the temperature changed quicker during 6 pm to 10 pm

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Step-by-step explanation:

a) The equation of the sphere having center (h,k,l) and radius r is

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