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Blizzard [7]
3 years ago
13

I NEED HELP PLEASE ITS DUE SOOM

Mathematics
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.

Edit: Explanation

The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.

In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)

In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)

To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.

8° / 2 = 4° per hour for 4-6 PM

9° / 4 = 2.25° per hour from 6-10 PM

Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.

yarga [219]3 years ago
6 0

Answer:

i agree with Mai because she/he (im not really sure) said that the temperature changed quicker in the time between 6 and 10 pm. the temperature change was 9 in those 4 hours.

Step-by-step explanation:

well there's a 4 hour difference between all 3 of the times

4 pm - 6pm

25 - 17 = 8

8 degree difference

6 pm - 10 pm

17 - 8 = 9

9 degree difference

the temperature changed quicker during 6 pm to 10 pm

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There are 95 candies in the dish.19 of the candies are chocolate. What percent of the candies are left
r-ruslan [8.4K]

Answer:

80%

Step-by-step explanation:

20% of the candies are chocolate, leaving the rest of the 80%

4 0
3 years ago
Solve the equation below for x.<br><br> -1<br> 2(3x - 4) = 11
kumpel [21]
If the -1 is not included, then your answer is 3.17.

2(3x-4)=11

3x2=6 and -4x2= -8

6x-8=11

+8 +8

6x=19

/6 /6


X= 3.17
7 0
3 years ago
Read 2 more answers
1/6d + 2/3 = 1/4(d-2)
KonstantinChe [14]
\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \\ \frac{d}{6}^{(2}}+\frac{2}{3}^{(4}=\frac{d-2}{4}^{(3} \\ \\ 2d+8=3(d-2) \\ \\ 2d+8=3d-6 \\ \\ 2d-3d=-6-8 \\ \\ -d=-14 \\ \\ \boxed{d=14}
4 0
3 years ago
Solve for X: 2(x + 5) + 3(x – 2) = 29<br> please explain too! will mark brainliest
8090 [49]

Answer:

5

Step-by-step explanation:

2x+10+3x-6=29

5x+4=29

5x=25

x=5

3 0
3 years ago
Write a quadratic equation ax²+ bx + C = 0, whose coefficients are a =-9, b = 0, c = -2
aksik [14]
<h3>ax² + bx + c = 0</h3>

<em>Let's write -9 where we see A</em><em>:</em>

<h3>-9x² + bx + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>

<h3>-9x² + 0.x + c = 0</h3>

<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>

<h3>-9x² + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>

<h3>-9x² + -2 = 0</h3>

<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>

<em>Let's put the known and the unknown on different sides:</em>

<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>

<h3>-9x² = 2</h3>

<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<h3>x² = 2/-9</h3>

<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>

<em>Please do not report</em><em>:</em><em>(</em>

<em>I hope I got it right, I'm trying to improve my English a little :)</em>

<h3><em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>

<h3><em><u>#XBadeX</u></em></h3>
8 0
3 years ago
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