Question

How many solutions does this system have? y = 3 x minus 5. y = negative x + 4. one two an infinite number no solution

Answer 1

Answer:

One

Step-by-step explanation:

It is given that,

y = 3x-5 ....(1)

y = -x+4 .....(2)

We can solve the above equations using substitution method. Put the value of y from equation (1) to equation (2) such that,

$3x-5 = -x+4\\\\3x+x = 5+4\\\\4x = 9\\\\x=\dfrac{9}{4}$

Put the value of x in equation (1) we get :

$y = 3x-5\\\\y = 3\times \dfrac{9}{4}-5\\\\y=\dfrac{7}{4}$

It means that the value of x is $\dfrac{9}{4}$ and the value of y is $\dfrac{7}{4}$. Hence, the given equations has only one solution.