Ryan will need 6 pounds of meatloaf. If you want to know how I got my answer, my work along with the answer will be shown below:
3/4 pound=1 small meatloaf
*Multiply 3/4 pound by 8 because he wants to make 8 small meat loaves, or just add 3/4+3/4+3/4+3/4+3/4+3/4+3/4+3/4*.
#1 way (recommended): 3/4*8/1=24/4....=6 pounds
#2 way: 3/4+3/4=6/4+3/4=9/4+3/4=12/4+3/4=15/4+3/4=18/4+3/4=21/4+3/4=24/4=6 pounds
I hope this helps! Let me know if you still need help!
(2 - 7z)(2 + 7z)
= (2)^2 - (7z)^2
= 4 - 49z^2
Problem 1)
AC is only perpendicular to EF if angle ADE is 90 degrees
(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE = 88
Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle
Triangle AED is acute (all 3 angles are less than 90 degrees)
So because angle ADE is NOT 90 degrees, this means
AC is NOT perpendicular to EF-------------------------------------------------------------
Problem 2)
a)
The center is (2,-3) The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2
---------------------
b)
The radius is 3 and the diameter is 6From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2
where
h = 2
k = -3
r = 3
so, radius = r = 3
diameter = d = 2*r = 2*3 = 6
---------------------
c)
The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.
Some points on the circle are
A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)
Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.
3000 +400+60+5 is the answer.hope I helped you