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tatyana61 [14]
2 years ago
10

I need help, I don't just need to answer I need to know the steps on how to solve it asap

Mathematics
1 answer:
Likurg_2 [28]2 years ago
3 0
Your goal when solving problems like these are to get V by itself. Meaning, on one side of the equal sign. So first you are to add -2 over to the side with the 4. Then multiple that by 11. To undo the division
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Jane has a checkbook balance of $68.00. She then writes two checks, one for $5.00 and one for $62.50. She also deposits $75.00.
nataly862011 [7]
That would be D. The first two would be fight (I think) except they don't include turning the calculator on. C is just plain wrong. D has all the right keystrokes.
8 0
3 years ago
100 POINTS!!! Please solve this question step by step and explain each step for 100 points.
djverab [1.8K]

2\dfrac 29 = -\dfrac 45  m \\\\\implies 2+ \dfrac 29 =- \dfrac 45 m \\\\\implies \dfrac{20}9 = -\dfrac 45 m \\\\\implies 5(20) = (-4m)9\\\\\implies 100 = -36m\\\\\implies m = -\dfrac{100}{36} \\\\\implies m =  -\dfrac{25}9\\\\\implies m=-2\dfrac 79

3 0
2 years ago
Read 2 more answers
Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N <= k), k = 1,2,... Check
vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0
3 years ago
P = A + B + C Find P if A = 23 B = 17 C = 29 P=​
madam [21]

Answer:

P = 69!

Step-by-step explanation:

23+17+29 = 69 :)

3 0
3 years ago
Read 2 more answers
A spinner with 12 equal sections is spun. Each section is numbered 1 to 12. What Is the probability of landing on an odd number.
Bezzdna [24]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
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