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2 years ago

I need help, I don't just need to answer I need to know the steps on how to solve it asap

Mathematics

1 answer:

Likurg_2 [28]2 years ago

3 0

Your goal when solving problems like these are to get V by itself. Meaning, on one side of the equal sign. So first you are to add -2 over to the side with the 4. Then multiple that by 11. To undo the division

You might be interested in

Tan x + pi / 6 what is this equal to?

Scilla [17]

If tan (x)+pi/6=0

thn

tan (x)=-pi/6

take atan of both sides

x=atan (-pi/6)
x= -0.4823 rad
= -27.636 deg

5 0

3 years ago

an oil spreads 25 square meters every 10 minutes. how much area will the oil spill cover after 1 hour?

professor190 [17]

You know that every 10 minutes the oil moves 25 meters so and in 1 hour there are 60 minutes the equation is 60/10(25) and then you solve

The answer is 150 meters squared

3 0

3 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

2 years ago

A woman plans to use one fourth of a 48 foot x 100 foot rectangular backyard to plant garden. Find the perimeter of the garden i

nataly862011 [7]

Answer: 160ft.

Step-by-step explanation:

First find the area of the 48ft x 100ft rectangular back yard.

Area of a rectangular = L x B

= 48 x 100

= 4800ft²

Now, find 1/4 of the rectangular backyard meant for garden

= 1/4 of 4800

= 1200ft²

Step 2:

To find the perimeter of the garden,first find the length and breath of the garden. From the dimension of the garden, the length is 40ft > width. In interpreting this,

We make the width of the garden to be. B = xft,

Therefore. L = (x + 40)ft

Now equate the product of this to 1200ft

x(x + 40) = 1200

Open the bracket

x² + 40x = 1200

x² + 40x - 1200 = 0

This is now a quadratic expression. Solving for x using any methods

x² + 60x - 20x - 1200 = 0

Solving by grouping

x(x + 60) - 20(x + 60) = 0

Collect common factors here

(x + 60)(x - 20) = 0

Therefore, x = -60 or 20

Remember, x cannot be negative, so x = 20ft. The width = 20ft, and the length = 60ft.

With this, we can determine the perimeter.

Formula for perimeter of a rectangular block

= 2( L + B )

= 2( 60 + 20 )

= 2(80)

= 2 x 80

= 160ft.

8 0

3 years ago

The quantity is called the pooled variance estimate of the common variance of two unknown but equal population variances. It is

lozanna [386]

Answer:

sample variances

Step-by-step explanation:

The pooled variance method is used to estimate the variance of several different population with different means, but are assume to have the same variance.

The weights represent the sample variances.

So the correct answer is

sample variances

5 0

3 years ago