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3 years ago

10

I need help, I don't just need to answer I need to know the steps on how to solve it asap

1 answer:

Likurg_2 [28]3 years ago

3 0

Your goal when solving problems like these are to get V by itself. Meaning, on one side of the equal sign. So first you are to add -2 over to the side with the 4. Then multiple that by 11. To undo the division

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Solve for x the triangles In Each pair LMN~LRS <br> Please help quickly and show work pleasee

Gala2k [10]

Given:

$\Delta LMN\sim \Delta LRS$

To find:

The value of x.

Solution:

We have,

$\Delta LMN\sim \Delta LRS$

We know that the corresponding sides of similar triangles are proportional. So,

$\dfrac{LM}{LR}=\dfrac{LN}{LS}$

$\dfrac{18}{2x-18}=\dfrac{30}{10}$

$\dfrac{18}{2x-18}=3$

$18=3(2x-18)$

Using distributive property, we get

$18=3(2x)-3(18)$

$18=6x-54$

$18+54=6x$

$72=6x$

Divide both sides by 6.

$\dfrac{72}{6}=x$

$12=x$

Therefore, the correct option is A.

7 0

3 years ago

her teacher has informed her that her final answer is wrong. Explain to Jessley where she made a mistake and why

ahrayia [7]

Answer:

3

Step-by-step explanation:

4 0

3 years ago

Please answer the question below.

tatuchka [14]

Answer:

The answer is the 2nd and 4th one

6 0

3 years ago

The speeds of vehicles traveling on a highway are normally distributed with a population standard deviation of 7 miles per hour

True [87]

Answer: $(56.03\ ,63.97)$

Step-by-step explanation:

Given : The speeds of vehicles traveling on a highway are normally distributed .

Standard deviation: $\sigma: 7$

Since , sample size : $n=20$ , which is small sample (n<30) so the test applied here is a t-test.

Degree of freedom= $n-1=20-1=19$

Sample mean : $\overline{x}=60$

Level of significance : $1-\alpha:0.98$

Then , significance level : $\alpha: 1-0.98=0.02$

Using t-distribution table , Critical value : $\text{t-score}=t_{n-1, \alpha/2}= 2.539483$

The confidence interval for population mean is given by :-

$\overline{x}\pm t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

$60\pm( 2.539483)\dfrac{7}{\sqrt{20}}\approx60\pm3.97=(56.03\ ,63.97)$

Hence, a 98% confidence interval for the population mean= $(56.03\ ,63.97)$

4 0

3 years ago

Ill mark brainlist plss help

crimeas [40]

Answer:

Hey mate.....

Step-by-step explanation:

This is ur answer....

<h2>○ 28 cm2 </h2>

Hope it helps!

Mark me brainliest pls....

Follow me! ;)

3 0

3 years ago

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