Question

Find an equation of the line passing through the point (−6,−5) that is parallel to the line y=4/3x−5

Answer 1

Answer:

The answer is

$y = \frac{4}{3} x + 3$

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

y = 4/3x - 5

Comparing with the general equation above

Slope/ m = 4/3

Since the lines are parallel their slope are also the same

So we have

Slope of parallel line = 4/3

Equation of the line using point (−6,−5) and slope 4/3 is

$y + 5 = \frac{4}{3} (x + 6) \\ y + 5 = \frac{4}{3} x + 8 \\ y = \frac{4}{3} x + 8 - 5$

We have the final answer as

$y = \frac{4}{3} x + 3$

Hope this helps you.