The answer to this question is:
A circle is growing so that the radius is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.?
✔️I assume here the linear scale is changing at the rato of 5cm/min
✔️dR/dt=5(cm/min) (R - is the radius.... yrs, of the circle (not the side)
✔️The rate of area change would be d(pi*R^2)/dt=2pi*R*dR/dt.
✔️At the instant when R=20cm,this rate would be,
✔️2pi*20*5(cm^2/min)=200pi (cm^2/min) or, almost, 628 (cm^2/min)
Hoped This Helped, <span>Cello10
Your Welcome :) </span>
Answer: i’m not sure if it’s just simplifying or factoring. but for simplifying it equals. 1/8 or .125
Explanation: calculator
3.28·3 = 9.84 is the same as:
3.28+3.28+3.28 = 9.84
Hope this helped! Good luck!
<u>Answer:</u>
1/9 > -4
because -4 is a negative no less than 0. whereas 1/9 is a positive no greater than 0.
So negative no can't be greater than positive no.
