Answer:
a. HCl.
b. 0.057 g.
c. 1.69 g.
d. 77 %.
Explanation:
Hello!
In this case, since the reaction between magnesium and hydrochloric acid is:
Whereas there is 1:2 mole ratio between them.
a) Here, we can identify the limiting reactant as that yielded the fewest moles of hydrogen gas product via the 1:1 and 2:1 mole ratios:
Thus, since hydrochloric yields fewer moles of hydrogen than magnesium, we realize it is the limiting reactant.
b) Here, we use the molar mass of gaseous hydrogen (2.02 g/mol) to compute the mass:
c) Here, we compute the mass of magnesium associated with the yielded 0.0248 moles of hydrogen:
Thus, the mass of excess magnesium turns out:
d) Finally, we compute the percent yield, considering 0.044 g is the actual yield and 0.057 g the theoretical yield:
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<span>H-1 means that the isotope has mass number 1: it has 1 proton. H-2 means that the isotope has mass number 2: so it has 1 proton and 1 neutron. H-3 means the isotope has 1 proton and 1 neutron. As you see all the isotopes have the same number of protons (atomic number), therefore they also have the same number of electrons. What defines (differentiate) isotopes is the number of electrons. So, fill the table such that the number of protons and electrons is 1 for all the isotopes, and the number of neutrons are 0 for H-1, 1 for H-2, and 2 for H-3.</span>
<span>The rate of substance B
being consumed should be equal to that of the substance A. Dynamic equilibrium
is the balance in a process that is continuing. It is achieved in a reaction
when the forward rate of reaction and the backward rate of reaction is at the
same value or equal.</span>
Answer:
3.8 is the van't Hoff factor for iron(III) chloride in X.
Explanation:
where,
=depression in freezing point =
= freezing point constant
m = molality =
i = van't Hoff factor
we have :
Mass of glycine = 63.4 g
Molar mass of glycine = 71 g/mol
Mass of solvent X = 700. g = 0.7 kg
1 g = 0.001 kg
of solvent X= ?
i = 1 (non electrolyte)
Depression in freezing point=
When iron(III) chloride is dissolved in 0.7 kg of solvent X
Mass of iron(III) chloride = 63.4 g
Molar mass of iron(III) chloride= 162.5 g/mol
Mass of solvent X = 700. g = 0.7 kg
1 g = 0.001 kg
of solvent X=
i = ?
Depression in freezing point:
Solving for i:
i = 3.85 ≈ 3.8
3.8 is the van't Hoff factor for iron(III) chloride in X.
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