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Alexandra [31]
3 years ago
8

Una solución formada por 58 gramos de cloruro de sodio (NaCl) en 100 mL de solución posee una concentración

Chemistry
1 answer:
masya89 [10]3 years ago
8 0

Answer:

58

Explanation:

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If there were 10 grams of a radioactive isotope, how much of the sample would be left after 1 half-life? How much after 2 half-l
Vikentia [17]
One half-life: 5 grams
Two half-lives: 2.5 grams
3 0
3 years ago
PLEASE HELP ME WITH PHYSICAL SCIENCE!! PRETTY EASY QUESTION ​
Umnica [9.8K]

Explanation:

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7 0
3 years ago
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a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is
NeX [460]

Answer:

The specific heat of iron is 0.45 J/g.°C

Explanation:

The amount of heat absorbed by the metal is given by:

heat = m x Sh x ΔT

From the data, we have:

heat = 180.8 J

mass = m = 22.44 g

ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C

Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT)  = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

8 0
3 years ago
16.0 grams of molecular oxygen gas is equal to
IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

To get the number of molecules present in 16 grams of O2, we will use the formula:

         No. of molecules = no. of moles x Avogadro's number (NA)-----  eq 1)

As we know:

                        The number of moles = mass/ molar mass of molecule

Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

Putting the values in above formula:

                                                    = 16/32  

                                                     = 0.5 moles

Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

                                No. of molecules = 0.5  x 6.02 * 10^23

                                   =3.01 x 10^23 molecules

or                 301,000,000,000,000,000,000,000 molecules

This means that 16 grams of 3.01 x 10^23 molecules of oxygen.

Hope it helps!

4 0
3 years ago
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Consider the gold isotope 197Au. How many electrons, protons, and neutrons are in a neutral 197Au atom?
tangare [24]

Answer:

The 197Au isotope has 79 protons, 79 electrons and 118 neutrons

Explanation:

Step 1: The isotope = 197Au

Step 2: Calculate neutrons, electrons and protons

197 = Number of protons + number of neutrons

Isotopes always have the same proton number ( is the same as the atomic number). For Gold (Au) is this 79.

The number of electrons is equal to the number of protons in a neutral atom. Since we have 79 protons, there are also 79 electrons.

All isotopes of Au have a different number of neutrons.

The number of neutrons = 197 -79 = 118 neutrons

The 197Au isotope has 79 protons, 79 electrons and 118 neutrons

6 0
3 years ago
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