Una solución formada por 58 gramos de cloruro de sodio (NaCl) en 100 mL de solución posee una concentración

nikklg [1K]

Hey there,

I hope this answer solves your doubt.

Step-by-step Explanation:-

The question is asking if the bonds between Carbon and Chlorine in CCl4 will be single, double or triple bonds.

(The structure of CCl4 is attached as picture. Check it)

As per image, the structure consists of Single bonds. It is 4 single bonds.

4 0

2 years ago

A vertical piston-cylinder device contains water and is being heated. During the heating process, 70 kJ of heat is transferred t

nydimaria [60]

Answer:

Energy change = 59. 5 kJ

Explanation:

First, we collect the data:

Let:

Q (supplied) be the energy supplied to the water

Q (lost) be energy lost to surroundings

Q (piston) be the energy possessed by the piston as it moves up

v = volume flow (m³/s)]

V = velocity of the gas (m/s)

mass = 50 kg

Second, calculate the work done by the piston:

to find velocity, we use this formula:

v = A × V

Therefore, V = 0.5 (m³/s)/0.005 m²

= 10 m/s

it means the water is evaporating at a rate of 10 m/s

the evaporating water transfers energy to the piston, kinetic energy Ek

Ek = 1/2 mV²

= 0.5 (50) ( 10) ²

= 2 500 J

= 2.5 kJ

The net energy, ΔQ is given by:

ΔQ (net) = Q (supplied) - Q (piston) - Q (lost)

= 70 - 2.5 -8

= 59.5 kJ Ans

7 0

3 years ago

Given the two half-reactions, what must be done in the next step before the reaction can be balanced? Au3+ --> Au I- --> I

Artyom0805 [142]

Answer:

The balance equation is

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

Explanation:

first, we have to make sure that the atoms are balanced

$Au^{+3}$ → $Au^{}$

$2I^{-}$ → $I_{2}$

then we proceed to balance charges of each half-reaction

$Au^{+3} + 3e^{-}$ → $Au^{}$

$2I^{-}$ → $I_{2}$ $+ 2e^{-}$

Now we multiply the half-reactions to match the number of electrons in each one

( $Au^{+3} + 3e^{-}$ → $Au^{}$ )x2

( $2I^{-}$ → $I_{2}$ $+ 2e^{-}$ )x3

and now we do the sum of the half-reactions

2 $Au^{+3} + 6e^{-}$ → 2 $Au^{}$

$6I^{-}$ → 3 $I_{2}$ $+ 6e^{-}$

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

note: the only atom that needed to be balanced was I

3 0

4 years ago

Read 2 more answers

(9443+45−9.9) (9443+45−9.9) ×8.4× 10 6

ozzi

Booooooommmm!.................

6 0

4 years ago

Washing soda is a hydrate of sodium carbonate. Elemental analysis of a sample of washing soda gave 4.20% C and 7.05% H. What is

kozerog [31]

Answer:

Na₂CO₃ · 10H₂O

Explanation:

The formula for sodium carbonate hydrate is:

Na₂CO₃ · xH₂O

The unknown "x" is the number of water molecules contained in the hydrate.

To find "x" we have to use the hydrogen percentage in the sample, 7.05 % H.

First we calculate the molecular weight of Na₂CO₃ · xH₂O:

molecular weight of Na₂CO₃ · xH₂O = 23 × 2 + 12 + 16 × 3 + 18x

molecular weight of Na₂CO₃ · xH₂O = 106 + 18x g/mole

Now we devise the fallowing reasoning tanking in account 1 mole of Na₂CO₃ · xH₂O:

if in 106 + 18x grams of Na₂CO₃ · xH₂O we have 2x grams of hydrogen

then in 100 grams of Na₂CO₃ · xH₂O we have 7.05 grams of hydrogen

106 + 18x = (100 × 2x) / 7.05

106 + 18x = 28.4x

106 = 28.4x - 18x

106 = 10.4x

x = 106 / 10.4

x = 10.2 ≈ 10

The formula for the washing soda is Na₂CO₃ · 10H₂O.

5 0

3 years ago