Answer:
466.65 K
Explanation:
Using the formula of Pressure law,
P/T = P'/T'.................... Equation 1
Where P = Intial pressure of gas, T = Initial temperature of gas, P' = Final pressure of gas, T' = Final temperature of gas.
make T' The subeject of equation 1
T' = (P'T)/P................... Equation 2
From the question,
Given: P = 500 Torr = (500×133.322) N/m² = 66661 N/m², T = 35°C = (35+273) = 308 K, P' = 101000 N/m²( Standard pressure)
Substitute these values into equation 2
T' = (101000×308)/66661
T' = 466.65 K
A. It absorbs energy.
reactants are located on the left side of the equation, meaning energy among with other reactants were needed to get the reaction going, so it absorbed energy, which is also the endothermic process. The opposite of that would be having energy on the right side with the products which means that the reaction would've released energy which is the exothermic process. Hope this helps!
Answer:
1.553 M^2s^-1
Explanation:
Now let us consider experiments 1,2,3.
In experiment 1 and 2, the concentration of NO is doubled and the initial rate of reaction is quadrupled.
0.575/0.144 = 4
So;
2^2 =4
In experiment 2 and 3
The concentration of reaction of H2 is doubled and the rate of reaction is doubled.
0.575/0.287 = 2
2^1 =2
So we can now write;
Rate =k[NO]^2 [H2]^1
Taking up the first reaction;
0.144 =k [0.475]^2 [0.411]
k = 0.144/ [0.475]^2 [0.411]
k = 1.553 M^2s^-1
Answer:
Explanation:
From the information given:
(a)
(b)
(c)
∴
(d)
∴
(e)
∴
∴
Answer:
C- a method of testing an idea