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Marianna [84]
3 years ago
11

How many significant figures are in the number 020.310

Chemistry
1 answer:
True [87]3 years ago
6 0

Answer:

5

Explanation:

Sorry, don't have one

<u><em>Hope this helps and I get brainliest <3</em></u>

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Which is the greater distance 50 miles or 100 kilometers
slega [8]
The greater distance is 50 miles
4 0
3 years ago
__MgCl2 +
Anna35 [415]

Answer:

24.5 g of NaCl

Explanation:

We begin from the balanced reaction:

3MgCl₂ +   2Na₃PO₄  →    6NaCl   +  Mg₃(PO₄)₂

If the sodium phosphate is in excess, then the limting reagent is the magnessium chloride.

We convert mass to moles:

20 g . 1mol / 95.2g = 0.210 moles.

3 moles of MgCl₂ can produce 6 moles of NaCl

0.210 moles of salt, may produce (0.210 . 6) /3 = 0.420 moles

Ratio of reactant is twice the product

We convert the moles to mass:

0.420 mol .  58.45 g/mol = 24.5 g

6 0
3 years ago
13.8g element consist 4.6 ×10^22 atoms what is atomic mass of element?​
Keith_Richards [23]
<h2>~<u>Solution</u> :-</h2>
  • Here, to find the atomic mass of element, we must;

We know that,

  • 4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.

Thus,

The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;

=   \sf{\frac{13.8  \times 6.02 \times  {10}^{23} }{4.6 \times {10}^{22} } } \\

=  \sf{180.6 \: g \:  \: (molar \: mass)}

  • Hence, the molar mass (atomic mass) will be <u>180.6 g.</u>
8 0
2 years ago
Read 2 more answers
Sunspots sit on the sun’s
Crank

The answer is Photosphere Apex.      

7 0
3 years ago
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
 Zn =⇒ Zn+2(0.10) + 2e- (anode)
 Zn+2(?M) + 2e- === Zn(s) (cathode)
 
 Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn 
 E = E^o -0.0592 log Q; in this case E^o is zero. 
 E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2 
 23 mV x 1 volt/1000mv = 0.023 Volts 
 0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
 0.023 = -0.0296{ -1 - log[Zn+2] }
 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
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