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bazaltina [42]
2 years ago
15

What is the mass of an object that has a density of 12.7 g/cm3 and a volume of 57.9 cm

Chemistry
1 answer:
Nuetrik [128]2 years ago
6 0

Answer:

735.33 grams

Explanation:

mass = density × volume

= 12.7 × 57.9

= 735.33 grams

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What is the percent by mass of water in Na2SOa 10H20?total mass of element in compoundUse%Elementx 100molar mass of compoundO 5.
wlad13 [49]
Molar mass Na₂SO₄. 10H₂O = 322.19 g/mol

Molar mass  H₂O = 18.0

% Element =  molar mass / total mass x 100

% Element = 18 / 322,19 x 100 

% Element =  5.59 %

Answer A

hope this helps!

6 0
3 years ago
For each ionic compound formula, identify the main group to which X belongs: (c) X2SO4.
Zinaida [17]

The answer is group 1A.

In the ionic compound formula X₂SO₄, SO₄ has a -2 charge. Hence to balance this -2 charge of SO₄, X must have a +1 charge.

Group 1A elements form X⁺ type of ions because they are metals. So, they have the tendency to lose electrons.

Hence, X must belong to the 1A group.

Ionic Compounds-

  • Ionic compounds are formed by the electrostatic attraction between the anions and the cations.
  • Cations are positively charged ions that are formed due to the loss of electrons.
  • And the anions are negatively charged ions that are formed due to the gain of electrons.
  • Due to this, they have opposite charges and form bonds known as Ionic Bond.

To learn more about Ionic compounds, visit: brainly.com/question/9167977

#SPJ4

6 0
1 year ago
__NH4NO3 ---> _N2 + _H2O + _O2
Sveta_85 [38]

Answer:

It is decomposition synthesis Combustion.

Explanation:

It is used to produce dinitrogen monoxide and water. The reaction usually takes place in a place in a temperature of 200-260 degrees Celsius.

6 0
3 years ago
How much heat in j is giving out when 85.0g of lead cools from 200.0 c to 10.0c
photoshop1234 [79]

Answer:

q = - 2067.2 J of Heat is giving out when 85.0g of lead cools from 200.0 c to 10.0 c.

Explanation:

The Specific Heat capacity of Lead is 0.128 \frac{J}{g\ ^{0}C}

This means, increase in temperature of 1 gm of lead by 1 ^{0}\ C will require 0.128 J of heat.

Formula Used :

q = m.c.\Delta T

q = amount of heat added / removed

m = mass of substance in grams = 85.0 g

c = specific heat of the substance = 0.128

q = m.c.\Delta T = Change in temperature

                                          = final temperature - Initial temperature

                                          = 10 - 200

                                          = -190 ^{0}\ C

put value in formula

q = -  85\times 0.128\times 190

On calculation,

q = - 2067.2 J

- sign indicates that the heat is released in the process

5 0
3 years ago
The teacher in item 10 also needs to order plastic tubing. If each of the 60 students need 750 mm of tubing, what length of tubi
Alex777 [14]

45 m. If each student needs 750 mm of tubing, the teacher should order 45 m of tubing.

a) Find the <em>length in millimetres</em>

Length = 60 students x (750 mm tubing/1 student) = 45 000 mm tubing

b) Convert <em>millimetres to metres </em>

Length = 45 000 mm tubing x (1 m tubing/1000 mm tubing) = 45 m tubing

6 0
2 years ago
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