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bazaltina [42]
3 years ago
15

What is the mass of an object that has a density of 12.7 g/cm3 and a volume of 57.9 cm

Chemistry
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

735.33 grams

Explanation:

mass = density × volume

= 12.7 × 57.9

= 735.33 grams

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A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
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P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

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1 gallon is how many mm
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State whether the following liquids are miscible with hexane (C6H14) by entering "yes" or "no".
NeTakaya

Benzene, C6H6 is miscible with hexane (C6H14)  but iron (IIl) nitrate, and Sulfuric acid, H2SO4Fe(NO3)3 are not miscible with hexane (C6H14)

Since organic or non polar dissolves in nom polar solvent.here both benzene and hexane (C6H14) are non polar solvents.But iron (IIl) nitrate, Fe(NO3)3 and Sulfuric acid, H2SO4 are inorganic and polar, therefore cannot dissolve with non polar solvent like hexane.

Miscible is a flowery heard that oil and water aren't very miscible substances, while seltzer and orange juice are miscible and scrumptious.Miscible beverages are also described as liquids that can blend to form a homogeneous solution. Miscible drinks generally blend with out limit, meaning they may be soluble at all quantities.

Miscible approach the materials blend completely. If  substances are miscible, they're also absolutely soluble in each other no matter the order of creation. for example, tetrahydrofuran and water are miscible.

Learn more about miscible liquids here:-brainly.com/question/10423831

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3 0
2 years ago
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

3 0
3 years ago
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