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bazaltina [42]
3 years ago
15

What is the mass of an object that has a density of 12.7 g/cm3 and a volume of 57.9 cm

Chemistry
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

735.33 grams

Explanation:

mass = density × volume

= 12.7 × 57.9

= 735.33 grams

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The free energy change for the following reaction at 25 °C, when [Cd2+] = 1.20 M and [Fe2+] = 1.40×10-3 M, is -23.9 kJ: Cd2+(1.2
vladimir2022 [97]

Answer:

It's spontaneous in the reverse direction

Explanation:

A negative voltage indicate s that the reverse reaction is spontaneous (i.e. oxidation at the cathode, and reduction at the anode; by convention you would need to swap the labels on the electrodes)

8 0
3 years ago
Specific gravity is a number representing the ratio of a mineral's weight to the weight of an equal volume of water. TRUE FALSE
777dan777 [17]

Answer: True

Explanation: Specific Gravity of a body, also called its Relative Density, is the ratio of the density of that body to the density of a reference material (usually water).

With the Mathematics done right, it is evident that the specific gravity of a body would be equal to the ratio of mass/weight of the body to the mass/weight of an equal volume of water.

S.G = (Density of body)/(Density of water)

Density of Body = (mass/weight of body)/(volume of body)

Density of water = (mass/weight of water)/(volume of water)

If volume of Body = Volume of water, then,

S.G = (Mass/Weight of body)/(Mass/Weight of equal volume of water)

Proved!!

3 0
3 years ago
Please Help I will reward brainliest
8_murik_8 [283]
I think it is "Known".

Radioactive decay is measured using a formula where the half-life <span>of an isotope is the time it takes for the original nuclei to decay half of its original amount.</span>
7 0
3 years ago
Read 2 more answers
The solubility of copper chloride at 20 °C is 73 g/100 g of water. Kiera adds 100 g of copper chloride to 100 g of water and sti
OLEGan [10]

Answer:

m_{undissolved}=27g

Explanation:

Hello there!

In this case, according to the given information of the solubility of copper chloride, as the maximum amount of this salt one can dissolve without having a precipitate, we infer that since just 73 grams are actually dissolved, the following amount will remain solid as a precipitate:

m_{undissolved}=100g-73g\\\\m_{undissolved}=27g

Best regards!

3 0
2 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
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