Question

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 105°, a = 12 cm, c = 19 cm

Answer 1

Answer:

The area of triangle is $110.10cm^{2}$

Step-by-step explanation:

It is given that AB=19cm, BC=12cm and ∠B=105°

Now, Area of the triangle ABC=$\frac{1}{2}acsinB$

=$\frac{1}{2}{\times}12{\times}19{\times}sin105^{\circ}$

=$6{\times}19{\times}(0.965)$

=$110.10cm^{2}$

Thus, the area of triangle is $110.10cm^{2}$