Answer:
10
Step by step explanation:
In general, if we have an equation that has just one variable, such as x, then "solving the equation" means finding the set of all values that can be substituted for the one variable to produce a valid equation.
Isolate "x" on one side of the algebraic equation by adding the negative number that appears on the same side of the equation as the "x." For example, in the equation "x - 5 = 12", rewrite the equation as "x = 12 + 5" and solve for "x."
x + (-6) + (-8) = -4
x + (-6 + -8) = -4
x + (-14) = -4
x + (-14 + 14) = -4 + 14
x = 10
$482.5 is the FINAL ANSWER
To find commission:
We can use the base of 100% being 1650
We can use 5% because thats her commission
Use: 100(x)=1650(5) -> 100(x)=8250 after doing math, youll get the outcome of 82.5 commission
To find the total:
Just add that commission to her total being 82.5 + 400 = 482.5 $
It is 311.49. You would multiply 0.10 and 349.10, which is 34.61. Then subtract 34.61 from 349.10, which is 311.49. So, after a 10% discount of 346.10, the answer would be 311.49
Answer:
The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:
Step-by-step explanation:
We need to write equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3.
The equation for slope-intercept form is: 
where m is slope and b is y-intercept.
We are given slope m = -2/3 and we need to find y-intercept i.e b to write equation of line.
Using point (3,-1) and slope m=-2/3 we can find y-intercept i.e b
So, y-intercept b = 1
The equation of the line, in slope-intercept form, that passes through (3,-1) and has a slope = -2/3 is:
Answer:
a. i. x ≤ 25 ii. 16 < x < 35 iii. 25 < x ≤ 95
b. The second and third car seats are appropriate for a 35 lb child.
Step-by-step explanation:
a. Model those ranges with compound inequalities
Let x represent the car seat.
i. A car seat designed for a child weighing up to and including 25 lb is described by the inequality.
x ≤ 25
ii. A car seat designed for a child weighing between 16 lb and 35 lb is described by the inequality.
16 < x < 35
iii. A car seat designed for a child weighing between 25 lb and 95 lb inclusive is described by the inequality.
25 < x ≤ 95
b. Which car seats are appropriate for a 33-lb child?
Since 35 lb is included in the range of the inequalities for the second and third card seats, the second and third car seats are appropriate for a 35 lb child.
