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3241004551 [841]
3 years ago
6

Two parallel lines are crossed by a transversal . What is the value of k?

Mathematics
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

The value of is equal to k=60\°

Step-by-step explanation:

we know that

(2k+11)\°=131\° -----> by alternate exterior angles

solve for k

2k=131\°-11\°

k=120\°/2=60\°

MArishka [77]3 years ago
3 0

Answer:

the answer issss

Step-by-step explanation:

k=60

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Answer:1. The measure of angle P is 53.  2. The value of x is 25.

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Step-by-step explanation:

1. (3x +2) + (3x + 2 ) + (5x -11) =180  Angle Q and P have the same measures because it is an isosceles triangle that is why you have three expressions.

So x =17   and 3(17)+ 2 =53

2. (2x +10) + (2x+10) + (2x + 10)= 180 this is because the second triangle is an equilateral triangle which means all it have the same measures.

solve for x. and x  is 25.

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1/10y + 11= 3/5y -4

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Step-by-step explanation:

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A pole 10 feet tall is used to support a guy wire for a tower, which runs from the tower to a metal stake in the ground. After p
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Una torre de 28.2 m de altura esta situada a la orilla de un rio, desde lo alto del edificio el ángulo de depresión a la orilla
Svet_ta [14]

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

tan(\theta) = \frac{CO}{CA}

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}

Ahora, el ancho del río es:

CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!                  

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