Answer:
No, the opposite would be negative 6/4
Step-by-step explanation:
3/2 is just a simplified version of 6/4
Answer:
£45
Step-by-step explanation:
Given data
P= £300
R=5%
T= 3 years
SI= PRT/100
substitute
SI= 300*5*3/100
SI=4500/100
SI= £45
Hence the interest is £45
Answer:



And in the figure attached we see the limits with the percentages associated.
Step-by-step explanation:
For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%
We can find the limits and we got:



And in the figure attached we see the limits with the percentages associated.
I’m a little confused by the question and the problem, is there a picture of the problem you could add?
Y=mx
m=amount of time per day studied
y=time
x=number of days
we have
60=m(4)
divide by 4
15=m
y=15x