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3 years ago

8

What number is not part of the domain of the function g(x) = x+2/ x-1? How can you tell?

1 answer:

IrinaVladis [17]3 years ago

4 0

Answer:

yhgyh

Step-by-step explanation:

nfthfjfj

ffifjffghiyg

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Liz flips a coin 30 times. The coin lands heads up 21 times and tails up 9 times. Complete each

SSSSS [86.1K]

Answer:

$Pr = 0.50$

Step-by-step explanation:

Given

$n = 30$

$H = 21$

$T = 9$

See attachment for complete question

Required

$P(H)$

The question requires that we calculate the theoretical probability of landing on the head.

This means that, we have to ignore the given data, and we use the following

$S =\{H,T\}$ --- sample space

$n(S) = 2$ --- sample size

$n(H) = 1$ --- occurrence of Head

So, the theoretical probability is:

$Pr = n(H)/n(S)$

$Pr = 1/2$

$Pr = 0.50$

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2 years ago

10 divided by 1 7/8 = 4x what is x? hurry!!

Ostrovityanka [42]

X= 20/17 ; multiply by reciprocal 10 times 8/17 =4x then 80/17=4x , divide both sides by 4 leaves you x=20/17

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2 years ago

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PLLLLLLEEEEAAAAAAASSSSSSEEEEEE HEEELLLLLPPPPPP

uysha [10]

1.-5*2+10=0 : this is the answer

2. 1-5(7)=-34 =/= 4
1-10=-9 =/= 1
-4(7)+3=-25 =/= 1
-7+8=1 : this is the answer

3. the slope is $\frac{-10-(-5)}{-9-(-2)}= \frac{5}{7}$ . Answer C

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2 years ago

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Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

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2 years ago

Which statement describes a many to one function A. it is a linear function B. it is a non linear function C. it passes the hori

kobusy [5.1K]

The answer is a because its a

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3 years ago

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