True or False?

What is the answer ti 3\4 × g = 5/8

gladu [14]

For this case we have the following expression:

$\frac {3} {4} g = \frac {5} {8}$

We clear the value of the variable "g", for this:

We multiply by 4 on both sides of the equation:

$4 * \frac {3} {4} g = \frac {5} {8} * 4\\3g = \frac {20} {8}$

We divide by 3 on both sides of the equation:

$\frac {3g} {3} = \frac {20} {8 * 3}\\g = \frac {20} {24}$

We simplify:

$g = \frac {10} {12} = \frac {5} {6}$

Answer:

$g = \frac {5} {6}$

4 0

3 years ago

On Monday jack could lift 25lbs

kirill [66]

Answer:

he can still lift 25 or more

3 0

3 years ago

Please help me with this math problem, urgent please

Lady bird [3.3K]

Answer:

(X+2)(v-5)

Step-by-step explanation:

first, group and factor out the greatest common factor and combine to get (x+2)(v-5)

4 0

3 years ago

A boy has 3 red , 2 yellow and 3 green marbles. In how many ways can the boy arrange the marbles in a line if: a) Marbles of the

Ilya [14]

Answer:

The total number of different arrangements is 560.

Step-by-step explanation:

A multiset is a collection of objects, just like a set, but can contain an object more than once.

The multiplicity of a particular type of object is the number of times objects of that type appear in a multiset.

Permutations of Multisets Theorem.

The number of ordered n-tuples (or permutations with repetition) on a collection or multiset of $n$ objects, where there are $k$ kinds of objects and object kind 1 occurs with multiplicity $n_1$ , object kind 2 occurs with multiplicity $n_2$ , ... , and object kind $k$ occurs with multiplicity $n_k$ is:

$\begin{equation*}\frac{n!}{n_1!*n_2!*\dots * n_k!}\end{equation*}$

We know that a boy has 3 red, 2 yellow and 3 green marbles. In this case we have n = 8.

If marbles of the same color are indistinguishable, then the total number of different arrangements is

${8 \choose 3, 2, 3} = \frac{8 !}{3 ! 2 ! 3 !} = \frac{8\cdot \:7\cdot \:6\cdot \:5\cdot \:4}{2!\cdot \:3!}=\frac{6720}{2!\cdot \:3!}=\frac{6720}{12}=560$

8 0

3 years ago

Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the followin

svp [43]

Answer:

a) 1+2+3+4+...+396+397+398+399=79800

b) 1+2+3+4+...+546+547+548+549=150975

c) 2+4+6+8+...+72+74+76+78=1560

Step-by-step explanation:

We know that a summation formula for the first n natural numbers:

1+2+3+...+(n-2)+(n-1)+n=\frac{n(n+1)}{2}

We use the formula, we get

a) 1+2+3+4+...+396+397+398+399=\frac{399·(399+1)}{2}=\frac{399· 400}{2}=399· 200=79800

b) 1+2+3+4+...+546+547+548+549=\frac{549·(549+1)}{2}=\frac{549· 550}{2}=549· 275=150975

c)2+4+6+8+...+72+74+76+78=S / ( :2)

1+2+3+4+...+36+37+38+39=S/2

\frac{39·(39+1)}{2}=S/2

\frac{39·40}{2}=S/2

39·40=S

1560=S

Therefore, we get

2+4+6+8+...+72+74+76+78=1560

5 0

3 years ago