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weqwewe [10]
3 years ago
14

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0

Answer:

The standard form of quadratic equation is x^2-16x-36=0

The factored form of x^2-16x-36=0 is (x+2)(x-18)=0

Step-by-step explanation:

Given equation x^2-6=16x+30

We have to write  in standard form and then factorize the given equation.

The standard form for a general quadratic equation is given as ax^2+bx+c=0

Consider x^2-6=16x+30

Taking all terms to left side, we have,

x^2-6-16x-30=0

Adding like terms, we have,

x^2-16x-36=0

Now we will factorize it.

We will solve the quadratic equation x^2-16x-36=0 using middle term splitting method,

-16x can be written as -18x+2x

x^2-16x-36=0  becomes

\Rightarrow x^2-18x+2x-36=0

Taking x common from first two terms  and 2 common from last two terms we have,

\Rightarrow x(x-18)+2(x-18)=0

\Rightarrow (x+2)(x-18)=0

Thus, the factored form of x^2-16x-36=0 is (x+2)(x-18)=0

svetlana [45]3 years ago
4 0

Answer:

If your doing edgunity 2020 the correct as were are x=-2 or x=18 for second one on bottom then top is (x-18)(x+2)=0

Step-by-step explanation:

It’s asking about being written in standard form then factored those are the only two that can be rewritten in standard form then factored

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Ja'Von kicks a soccer ball into the air. The function f(x) = –16(x – 2)2 + 64 represents the height of the ball, in feet, as a f
Dima020 [189]

Answer:

The maximum height the ball reaches is 64 feet

Step-by-step explanation:

The given function is f(x) = -16·(x - 2)² + 64

From the equation, the path described by the ball is an inverted n-shaped parabola

The maximum height is therefore, the tip of the parabola

At the maximum height, the slope = 0 because the tip is momentarily flat

Since the slope (y₂ - y₁)/(x₂ - x₁)  = The derivative Δy/Δx, we find the derivative of the function and equate it to zero to find the coordinates at the  maximum height

Δy/Δx = dy/dx = d(-16·(x - 2)² + 64)/dx = -32·(x - 2) = -32·x + 64

To check if it is a maximum, we have;

d²y/dx² = d(-32·x + 64)/dx = -32 which is negative, indicating that the slope is reducing and we at the maximum point of the slope

Therefore for the maximum height Δy/Δx = dy/dx = -32·x + 64 = 0

64 = 32·x

x = 64/32 = 2 seconds

We now have the x-value at the slope, the f(x) value, is therefore;

f(2) = -16·(2 - 2)² + 64 = 64 feet

Therefore, the maximum height the ball reaches is 64 feet.

3 0
3 years ago
HELPPPPP!!! MATH HOMEWORK. IM STUMPED.
slavikrds [6]
First: 5
Second: 8
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Hope this helps! :)
~Zain
3 0
3 years ago
5 : 2 : 11 =.... : 6 : ....
lubasha [3.4K]
5:2:11=15:6:33
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7 0
3 years ago
Hello there!
jok3333 [9.3K]

Answer:

4. dy/dx = -2

8. dy/dx = 1/2 x^(-3/2)

10/ dy/dr = 4 pi r^2

Step-by-step explanation:

4.  y = -2x+7

dy/dx = -2(1)

dy/dx = -2

8.  y = 4 - x^-1/2

 dy/dx =  - (-1/2x^ (-1/2-1)

 dy/dx = 1/2 x^(-3/2)

10.  y = 4/3 pi r^3

dy/dr = 4/3 pi  (3r^2)

dy/dr = 4 pi r^2

7 0
3 years ago
PLEASE HELP
Drupady [299]

Answer:

2x+8-2y

Step-by-step explanation:

4x-2x+5+3-2y

2x+8-2y

8 0
3 years ago
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