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Natali [406]
3 years ago
10

Kelsey bought a circular rug that is 10 feet in diameter. The rug has a blue border and a red circular center that is 8 feet in

diameter. What is the area of the blue border
Mathematics
2 answers:
Dima020 [189]3 years ago
7 0

Answer: The answer is 2.


Step-by-step explanation: If the circular rug is 10ft across and the red is 8, then 10-8=2. 2 is the blue border.


Soloha48 [4]3 years ago
5 0

the blue rug is 2 feet in diameter because you specifically said all together it was 10 and they say the red rug is 8 feet which means you have to do 10-8=2


Hope this helps!!! Can u rate me brainiest and thank me

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5(-5x - 2) = 10(-5x+4)
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Answer:

5(-5x - 2) =

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-25x-10 = -50x+40

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A fair die is cast, a fair coin is tossed, and a card is drawn from a standard deck of 52 playing cards. Assuming these events a
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Answer:

The probability is 0.0192 to four decimal places.

Step-by-step explanation:

In this question, we are asked to calculate the probabilities that three events will occur at the same time.

Firstly, we identify the individual probabilities.

The probability of 6 showing In a throw of die is 1/6

The probability of a coin showing head in a flip of coin is 1/2

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Mathematically to get the probability of all these events happening, we simply multiply all together.

This will be ;

1/6 * 1/2 * 12/52 = 1/52 = 0.0192 ( to 4 decimal place)

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3 years ago
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When constructing parallel and perpendicular lines, how are the steps similar?
Schach [20]
Similar steps:

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12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
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\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

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As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

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