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3 years ago

PLEASEE HELPPPppppppp

Mathematics

2 answers:

Tomtit [17]3 years ago

8 0

Answer:

Answer it yourself buddy (:

Step-by-step explanation:

Talja [164]3 years ago

7 0

Answer:

The answer is C

Step-by-step explanation:

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6x+2=-8+3x+25 whats the answer to x?

Nitella [24]

Answer:

x = 5

Step-by-step explanation:

To find the value of x make sure to get it on one side

First subtract 3x from each side. This makes the equation now

3x + 2 = -8 + 25

Now see what 25 subtract by 8 is (17)

3x + 2 = 17

Next subtract 2 from both sides

3x = 15

Lastly, divide 15 by 3, making x equal 5

x = 5

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3 years ago

(sinA + cosA)/ (secA + cosecA) = sinA* cosA

OlgaM077 [116]

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Trigonometric Identities</u>

We'll prove that:

$\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\sin A*\cos A$

Recall:

$\displaystyle \sec A =\frac{1}{\cos A}$

$\displaystyle \csc A =\frac{1}{\sin A}$

Applying those definitions:

$\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\frac{\sin A+\cos A}{\frac{1}{\cos A}+\frac{1}{\sin A}}$

Adding the fractions:

$\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\frac{\sin A+\cos A}{\frac{\sin A+\cos A}{\cos A*\sin A}}$

Dividing the fractions:

$\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=(\sin A+\cos A)*\frac{\cos A*\sin A}{\sin A+\cos A}$

Simplifying:

$\displaystyle \frac{\sin A+\cos A}{\sec A+\csc A}=\cos A*\sin A$

Hence proved

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3 years ago