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kari74 [83]
3 years ago
8

Consider the balanced equation below.

Chemistry
2 answers:
Bumek [7]3 years ago
6 0

Answer : The correct option is, (2) 8 mole of hydrogen will react with 1 mole of sulfur.

Explanation :

The balanced chemical equation is,

8H_2+S_8\rightarrow 8H_2S

By the stoichiometry we conclude that, 8 moles of hydrogen react with 1 mole of sulfur to give 8 moles of hydrogen sulfide.

Hence, the correct options is, (2) 8 mole of hydrogen will react with 1 mole of sulfur.

Tanya [424]3 years ago
3 0
The balanced reaction shows 8 moles of hydrogen gas, H2, reacts with 1 mole of molecular sulfur, S8. The most likely prediction is the second answer, <span>8 mol of hydrogen will react with 1 mol of sulfur.</span>
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2) A common "rule of thumb" -- for many reactions around room temperature is that the
babunello [35]

The question is incomplete. The complete question is :

A common "rule of thumb" for many reactions around room temperature is that the rate will double for each ten degree increase in temperature. Does the reaction you have studied seem to obey this rule? (Hint: Use your activation energy to calculate the ratio of rate constants at 300 and 310 Kelvin.)

Solutions :

If we consider the activation energy to be constant for the increase in 10 K temperature. (i.e. 300 K → 310 K), then the rate of the reaction will increase. This happens because of the change in the rate constant that leads to the change in overall rate of reaction.

Let's take :

$T_1=300 \ K$

$T_2=310 \ K$

The rate constant = $K_1 \text{ and } K_2$ respectively.

The activation energy and the Arhenius factor is same.

So by the arhenius equation,

$K_1 = Ae^{-\frac{E_a}{RT_1}}$  and $K_2 = Ae^{-\frac{E_a}{RT_2}}$

$\Rightarrow \frac{K_1}{K_2}= \frac{e^{-\frac{E_a}{RT_1}}}{e^{-\frac{E_a}{RT_2}}} $

$\Rightarrow \frac{K_1}{K_2}=  e^{-\frac{E_a}{R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)}$

$\Rightarrow \ln \frac{K_1}{K_2}= - \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}=  \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

Given, $E_a = 0.269$ J/mol

           R = 8.314 J/mol/K

$\Rightarrow \ln \frac{K_2}{K_1}=  \frac{0.269}{8.314} \left(\frac{1}{300} -\frac{1}{310} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}=  \frac{0.269}{8.314} \times \frac{10}{300 \times 310}$

$\Rightarrow \ln \frac{K_2}{K_1}=  3.479 \times 10^{-6}$

$\Rightarrow  \frac{K_2}{K_1}=  e^{3.479 \times 10^{-6}}$

$\Rightarrow  \frac{K_2}{K_1}=  1$

∴ $K_2=K_1$

So, no this reaction does not seem to follow the thumb rule as its activation energy is very low.

8 0
2 years ago
If a sodium ion has 11 protons, 12 neutrons, and 11 electrons, what is the atomic mass of the atom?
iragen [17]

Answer:

23

Explanation:

we do not care about electrons, so 11 + 12 = 23

7 0
3 years ago
What is the pressure inside a 750 mL can of deodorant that starts at 15 degrees Celsius and 1.0 atm if the temperature is raised
Sonbull [250]

The answer is: the pressure inside a can of deodorant is 1.28 atm.

Gay-Lussac's Law: the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.

p₁/T₁ = p₂/T₂.  

p₁ = 1.0 atm.; initial pressure

T₁ = 15°C = 288.15 K; initial temperature.

T₂ = 95°C = 368.15 K, final temperature

p₂ = ?; final presure.

1.0 atm/288.15 K = p₂/368.15 K.  

1.0 atm · 368.15 K = 288.15 K · p₂.  

p₂ = 368.15 atm·K ÷ 288.15 K.  

p₂ = 1.28 atm.  

As the temperature goes up, the pressure also goes up and vice-versa.  

6 0
3 years ago
Develop a model to show the chemical potential energy of wood and how that energy is transformed.
Phantasy [73]

Answer:

Explanation:

Chemical potential energy is the chemical energy stored (or property) of a substance. One chemical potential energy of wood is combustion. Combustion involves the burning of a substance in excess oxygen (in this case open air). <u>The chemical energy stored here is transformed to thermal/heat energy after combustion due to the large amount of heat evolved/produced</u>.

NOTE:

The model above also that combustion is an exothermic reaction because it involves the release of heat into it's surrounding.

6 0
3 years ago
Particle Mass (g) Atomic mass Electrical charge (C) Relative
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Answer:



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