1) Chemical reaction
HCl + NaOH ---> NaCl + H2O
25.0 ml
0.150 M 0.250M
2) 50% completion => 0.025 l * 0.150 M * (1/2) = 0.001875 mol HCl consumed and 0.001875 mol HCl in solution
0.001875 mol HCl => 0.001875 mol H(+)
Volume = Volume of HCl solution + Volumen of NaOH solution added
Volume of HCl solution = 0.0250 l
Volume of NaOH = n / M = 0.001875 mol / 0.250M = 0.0075 l
Total volume = 0.0250 l + 0.0075 l = 0.0325 l
[H+] = 0.001875 mol / 0.0325 l = 0.05769 M
pH = - log [H+] = - log (0.05769) = 1.23
Answer: 1.23
3) Equivalence point
0.02500 l * 0.150 M = 0.250M * V
=> V = 0.02500 * 0.150 / 0.250 = 0.015 l
4) 1.00 ml NaOH added beyond the equivalence point
1.00 ml * 1 l / 1000 ml * 0.250 M = 0.00025 mol NaOH in excess
0.00025 mol NaOH = 0.00025 mol OH-
Volume of the solution = 0.02500 l + 0.015 l + 1.00/1000 l = 0.041 l
[OH-] = 0.00025 mol / 0.041 l = 0.00610 M
pOH = - log (0.00610) = 2.21
pH + pOH = 14 => pH = 14 - pOH = 14 - 2.21 = 11.76
Answer: 11.76
Answer:
The value of the equilibrium constant = 5.213
Explanation:
Here 
(equilibrium constant) is referred to as the partial pressure of product divided by the partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation
.
As such only gas appear in expression as solids takes a value of 1;
SO ; in the given equation from the question:
2 A (g) + B (s) ----> 2 C(s) + D (g)
![K_p = \dfrac{[D]}{[A]^2}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cdfrac%7B%5BD%5D%7D%7B%5BA%5D%5E2%7D)
The value of the equilibrium constant = 5.213
Co= 59g
S=32g
59+32=91g/mol
The magnitude of the force required to change the length of a spring-like object is directly proportional to the spring constant and the displacement of the spring. Elastic potential energy is directly proportional to the square of the change in length and the spring constant.
<em>Answer:</em>
- It behaves as the electron donar. Its is correct one
<em>Definition of lewis base:</em>
- Lewis base is a such a substance which donate pair of electron to Lewis acid.
<em>Example:</em>
H3N + BF3 ⇒ H3N---≥BF3
- Ammonia is a lewis base while boron trifluride is lewis acid.
<em>Condition</em>
- There should be lone pair of electron
- Negative charged substances or anions
