Answer:
The mole fraction of N₂ is 0.26.
Explanation:
The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:
PT = PA + PB
This relationship is due to the assumption that there are no attractive forces between the gases.
Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.
So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:
PA = XA * PT
In this case:
- PA= PN₂= 300 torr
- XA=XN₂= ?
- PT= 1.50 atm= 1140 torr (being 1 atm= 760 torr)
Replacing:
300 torr= XN₂*1140 torr
Solving:

XN₂= 0.26
<u><em>The mole fraction of N₂ is 0.26.</em></u>
Find the number of moles
C = n / V
C(Concentration) = 0.30 moles / L
V ( Volume) = 2 L
n = ??
n = C * V
n = 0.30 mol / L * 2 L
n = 0.60 mol
Find the molar mass
2Na = 23 * 2 = 46 grams
1S = 32 * 1 = 32 grams
O4 = 16 * 4 = 64 grams
Total = 142 grams / mol
Find the mass
n = given mass / molar mass
n = 0.06 mol
molar Mass = 142 grams / mol
given mass = ???
given mass = molar mass * mols
given mass = 142 * 0.6
given mass = 85.2 grams.
85.2 are in a 2 L solution that has a concentration of 0.6 mol/L
Answer:
The number of carbon atoms in the organic compound is 16.
Explanation:
The relative intensity of M + 1 peak (relative to M = 100) in organic compounds can be predicted by the following formula:
[M + 1] = (number of C x 1.07) ---------------------------------------------------- (1)
This formula can also be used to determine the number of carbon from the given intensity. But first, the intensity of [M + 1] relative to [M] = 100 needs to be determined, for which, consider the following calculations,
![[M+1]=(\frac{M+1}{M}) (100)](https://tex.z-dn.net/?f=%5BM%2B1%5D%3D%28%5Cfrac%7BM%2B1%7D%7BM%7D%29%20%28100%29)
![[M+1]=(\frac{7.022}{40.58}) (100)](https://tex.z-dn.net/?f=%5BM%2B1%5D%3D%28%5Cfrac%7B7.022%7D%7B40.58%7D%29%20%28100%29)
![[M+1]=17.30](https://tex.z-dn.net/?f=%5BM%2B1%5D%3D17.30)
Using equation 1 we get,
![number of C=\frac{[M+1]}{1.07}](https://tex.z-dn.net/?f=number%20of%20C%3D%5Cfrac%7B%5BM%2B1%5D%7D%7B1.07%7D)

or number of C = 16
The remaining value, 0.168, can be due to the isotopes of hydrogen and oxygen in the organic compound.