Explanation:
A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. It can be concluded that this gas has reached standard temperature and pressure.
Standard temperature is zero degree celcius which corresponds to 273.15 degree kelvin.
Standard pressure is 760 mmHg which corresponds to 101.325 kPa.
Answer:
97 000 g Na
Explanation:
The absortion (or liberation) of energy in form of heat is expressed by:
q=m*Cp*ΔT
The information we have:
q=1.30MJ= 1.30*10^6 J
ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)
Cp=30.8 J/(K mol Na)
If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.
To do so, we use the molar mass of Na= 22.99g/mol
![Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}](https://tex.z-dn.net/?f=Cp%3D%20%5Cfrac%7B30.8J%7D%7BK%2Amol%20Na%7D%2A%5Cfrac%7B1%20mol%20Na%7D%7B22.99%20g%20Na%7D%3D1.34%5Cfrac%7BJ%7D%7BK%2Ag%20Na%7D)
Now, we are able to solve for m:
=97 000 g Na
Attraction between a cation in one element and an anion in the other element
Nitrogen is 78.08% of the air is fills the earth's atmosphere.