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3 years ago

Which part of making a solution always releases energy?

1 answer:

4 0

<span>The part of making a solution that always releases energy is the overall change in forming the solution. The answer is letter D. Although letters A, B and C can be viable answers but, it is not always the case. There are some substances that when you mix or separate them requires more energy or less energy. An example would be w</span>hen the formation (or enthalpy of formation) of carbon dioxide is negative, it means that it releases heat to the surroundings. When it releases heat to the surroundings, the reaction is exothermic. Another example is when you mix baking soda and muriatic acid, the resulting mixture is colder. When it is cold, it means that the reaction is endothermic. So the best answer is letter D.

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What formula gives the ratio of elements?

USPshnik [31]

Answer:

In a chemical formula, the elements in a compound are represented by their chemical symbols, and the ratio of different elements is represented by subscripts.

Explanation:

6 0

2 years ago

Consider the equilibrium

Kamila [148]

Answer:

The answers are in the explanation

Explanation:

For the equilibrium:

B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq).

By LeChatelier's principle, the increase in the concentration of a reactant (for example) at equilibrium will change the system counteracting the increasing producing more product.

Thus,

A) Will the equilibrium constant for the reaction increase, decrease, or stay the same? Why? .

The equilibrium constant is a thermodynamic constant that stay the same with the addition of a compound.

B) Will the concentration of HB⁺(aq) increase, decrease, or stay the same? Why?

By LeChatelier's principle, the addition of B will induce the formation of more HB⁺(aq) increasing the concentration.

C) Will the pH of the solution increase, decrease, or stay the same? Why?

As the addition of B induce the increasing of OH⁻, the pH of the solution will increase.

I hope it helps!

7 0

3 years ago

What is an absolute zero of a temperature

Leviafan [203]

Answer:

Absolute zero temperature: Absolute zero is the temperature at which a substance have very low internal energy or in other words no heat energy in the particle.

Explanation: The temperature is very low and the particles are very cold. On cooling, speed of particle decrease. On the Celsius scale, - 273.15 is the absolute zero and on the Kelvin scale, 0 k is the absolute zero. On absolute zero temperature, the movement in the particles occurs at very low speed near to zero.

7 0

3 years ago

Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon

Vsevolod [243]

Answer:

The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)

Explanation:

First equation:

The reactants propane and water react to form the products CO and H2

C3H8(g) + 3H2O(g) → 3CO(g) + 7H2(g)

Second equation:

The products CO and H2 will react

CO(g) + H2O(g) → H2(g) + CO2(g)

We should multiply the equation by 3 (to equal the products of the first equation)

3CO(g) + 3H2O(g) → 3H2(g) + 3CO2(g)

Add the second to the first equation:

C3H8(g) + 3 H2O(g) + 3 CO(g) + 3 H2O(g) → 3 H2(g) + 3CO2(g) + 3 CO(g) + 7 H2(g)

The net chemical equation is: 6 H2O(g) + C3H8(g) → 10 H2(g) + 3 CO2(g)

3 0

2 years ago

How many grams of magnesium<br> sulfate (MgSO4) are dissolved in<br> 0.965 L of a 0.0575 M solution?

JulsSmile [24]

<h3>Answer:</h3>

6.68 g MgSO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.965 L

0.0575 M

<u>Step 2: Identify Conversions</u>

Molar Mass of Mg - 24.31 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol

Substitute [M]: 0.0575 M = x / 0.965 L
Isolate <em>x</em>: 0.055488 mol MgSO₄ = x
Rewrite: x = 0.055488 mol MgSO₄

<u>Step 4: Convert</u>

<u /> $\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} )$ = 6.67959 g MgSO₄

<u>Step 5: Check</u>

<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>

6.67959 g MgSO₄ ≈ 6.68 g MgSO₄

5 0

3 years ago