1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kupik [55]
3 years ago
13

If an individual is eating a diet in which 25% of their ATP production is a result of utilizing carbohydrates, 50% of their ATP

production is a result of metabolizing fats, 25% of their ATP production is a result of metabolizing proteins, their cardiac output is 4.7 L/min, and their arterial-venous oxygen difference is 6.2 mL/dL, how much carbon dioxide are they producing
Chemistry
1 answer:
NISA [10]3 years ago
5 0

Answer:

Oxidative phosphorylation proceeds with the formation of energy laden molecules i.e; carbondioxide and water.

Therefore, Total CO₂ production is directly related to VCO₂ = R x VO₂

where, R is the respiratory quotient varing among 0.7 to 1.0 according to the energy intake (ATP) ie 0.25 of the total diet consumed .

VO₂ is, as mentioned above arterial venous oxygen difference = 6.2ml/dl

therefore, VCO₂ = 0.25 x 6.2

= 1.55 ml/dl

ie; VO₂ : VCO₂ = 6.2 : 1.55.

Explanation:

You might be interested in
How many electrons does the isotope oxygen-18 have?<br> 6<br> 8<br> 10<br> 18
Alexxandr [17]
It has 8 electrons I the answer
7 0
3 years ago
Ter the symbol for the isotope used in blood flow analyses.
blondinia [14]

Answer:

The symbol of isotopes used for blood flow analysis is \begin{array}{c}{141} \\ {58}\end{array} C e.

<u>Explanation: </u>

  • Isotopes are the substances that exhibit the same atomic number but has a different mass number of an element.
  • The atomic number explains the number of protons present in the element and mass number explains the number of neutrons available in the element.
  • For blood flow analysis, the isotope element is cerium-141 and it is used in the chemical examination of blood flow particles.
  • Symbol used for this isotope is \begin{array}{c}{141} \\ {58}\end{array} C e, where 141 indicates the amount of mass present and 58 indicates the proton number and 83 indicates neutron number present in that element.
  • The amount of mass in an atom is calculated by the sum of protons and neutrons present in it. Thus mass of isotope is 141 obtained by the sum of 58 protons and 83 neutrons present in that isotope.
8 0
3 years ago
The bomb calorimeter in Exercise 102 is filled with 987g water. The initial temperature of the calorimeter contents is 23.32. A
Sholpan [36]

Answer:

25.907°C

Explanation:

In Exercise 102, heat capacity of bomb calorimeter is 6.660 kJ/°C

The heat of combustion of benzoic acid is equivalent to the total heat energy released to the bomb calorimeter and water in the calorimeter.

Thus:

-q_{combust} = q_{water} + q_{calori}

q_{combust} = heat of combustion of benzoic acid

q_{water} = heat energy released to water

q_{calori} = heat energy released to the calorimeter

Therefore,

-m_{combust}*H_{combust} = [m_{water}*c_{water} + C_{calori}]*(T_{f} - T_{i})

1.056*26.42 = [0.987*4.18 + 6.66](T_{f} - 23.32)

27.8995 = [4.12566+6.660](T_{f} - 23.32)

(T_{f} - 23.32) = 27.8995/10.7857 = 2.587

T_{f} = 23.32 + 2.587 = 25.907°C

4 0
3 years ago
The combustion of palmitic acid is represented by the chemical equation: C16H32O2(s) + 23O2(g) → 16 CO2(g) + 16 H2O(l) The magni
solniwko [45]

Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)

Generally \Delta  H  =  \Delta  U + \Delta N*  RT

Here \Delta  H is the change in enthalpy

\Delta  U is the change in the internal energy

              \Delta N  is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is O_2 and  CO_2 and this are both gases so the change would occur in the number of moles

So  

\Delta  H  =  \Delta  U + [16 -23]*  RT

\Delta  H  =  \Delta  U -7RT

The  negative sign in the equation tell us that the enthalpy\Delta_r H would be less than the Internal energy \Delta_r U

4 0
3 years ago
If metal ions in a solution were reduced, what would you expect to see?
marysya [2.9K]

Answer:

Solid metal

Explanation:

The reduced form of metal ions is the metal in elemental state (simple substance). So, if you have a solution with metal ions and they are reduced, you probably will see the deposition of the metal. For example: if you have a solution with sodium ions (Na⁺), and the ions are then reduced, you will see the aparition of a solid phase of metallic sodium (Na(s)), according to the following half-reaction:

Na⁺ + e- → Na(s)

8 0
2 years ago
Other questions:
  • A student buys a rope at the store. The label on the packaging says that the rope is 2.15 meters in length. The student measures
    14·1 answer
  • How do evaporation and boiling differ?
    9·2 answers
  • The pH scale for acidity is defined by pH=−log10[H⁺] where [H⁺]is the concentration of hydrogen ions measured in moles per liter
    5·1 answer
  • Under what circumstances will a scientific theory be changed or discarded? A. New experimental evidence is not compatible with t
    11·2 answers
  • "the osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
    14·2 answers
  • _______ rock can be changed directly into _______ rock with the application of heat and pressure.
    8·1 answer
  • ILL GIVE BRAINLISTS!!!!!
    7·2 answers
  • Match the standard reduction potentials for each half reaction and the electric potential for the voltaic cell.
    7·1 answer
  • The 3 types of heat transfer are convection, radiation, connected.<br> A. True<br> B. False
    13·1 answer
  • 1. What happens when an environment reaches its carrying capacity?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!