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3 years ago

5 + 17 + 29 + 41 + 53 What is the 12th term of the series

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

7 0

The answer is 137 your welcome

tensa zangetsu [6.8K]3 years ago

4 0

To get the 12th term, first find the rule of the series. To do so, subtract 17 by 5 which gives you 12.
You can do the same to other numbers by subtracting the number before the number you chose.
For example, 41.
41 subtracted with 29 results with 12.
The rule for this series is +12.
So each number is added by 12 to reach towards the next.
The 5th term 53 +12 =65,
the 6th term65 +12= 77,
the 7th term 77 +12 =89,
the 8th term 89+12= 101,
the 9th term 101 +12= 113,
the 10th term 113 + 12= 125
the 11th term 125 + 12 = 137,
the 12th term 137 + 12= 149.

Answer: 12th term of the series is 149.

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Anastaziya [24]

Answer:

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Step-by-step explanation:

we would like to figure out the derivative of the following:

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to do so, let,

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By constant derivation we acquire:

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use exponent rule of derivation which yields:

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simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

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