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Rzqust [24]
2 years ago
14

5 + 17 + 29 + 41 + 53 What is the 12th term of the series

Mathematics
2 answers:
Nezavi [6.7K]2 years ago
7 0
The answer is 137 your welcome
tensa zangetsu [6.8K]2 years ago
4 0
To get the 12th term, first find the rule of the series. To do so, subtract 17 by 5 which gives you 12.
You can do the same to other numbers by subtracting the number before the number you chose.
For example, 41.
41 subtracted with 29 results with 12.
The rule for this series is +12.
So each number is added by 12 to reach towards the next.
The 5th term 53 +12 =65,
the 6th term65 +12= 77,
the 7th term 77 +12 =89,
the 8th term 89+12= 101,
the 9th term 101 +12= 113,
the 10th term 113 + 12= 125
the 11th term 125 + 12 = 137,
the 12th term 137 + 12= 149.

Answer: 12th term of the series is 149.
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Please help me........
kati45 [8]

Answer:

x = 54

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-12(x + 4) + 14x = 60

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute -12:                              -12x - 48 + 14x = 60
  2. Combine like terms:                   2x - 48 = 60
  3. Add 48 to both sides:                 2x = 108
  4. Divide 2 on both sides:              x = 54
7 0
3 years ago
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Convert .06 yards to inches. A) 2.16 inches B) 2.88 inches C) 21.6 inches D) 28.8 inches
sweet-ann [11.9K]
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7 0
3 years ago
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Write a number in scientific notation that is between 0 and 1/3 . justify the response .
Airida [17]
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3 0
3 years ago
a box of crackers has a volume of 48 cubic inches. what is the volume of a similar box that is smaller by a scale factor of 2/3
earnstyle [38]
For this case what you need to know is that the original volume of the cookie box is:
 V = (w) * (l) * (h)
 Where,
 w: width
 l: long
 h: height.
 We have then:
 V = (w) * (l) * (h) = 48 in ^ 3
 The volume of a similar box is:
 V = (w * (2/3)) * (l * (2/3)) * (h * (2/3))
 We rewrite:
 V = ((w) * (l) * (h)) * ((2/3) * (2/3) * (2/3))
 V = (w) * (l) * (h) * ((2/3) ^ 3)
 V = 48 * ((2/3) ^ 3)
 V = 14.22222222 in ^ 3
 Answer:
 the volume of a similar box that is smaller by a scale factor of 2/3 is:
 V = 14.22222222 in ^ 3
6 0
3 years ago
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