2 years ago

What is the standard deviation of a normal distribution, whose mean is 35, in which an x-value of 23 has a z-score of -1.63?

1 answer:

Dvinal [7]2 years ago

6 0

Answer:

7.36

Step-by-step explanation:

z-score is:

z = (x − μ) / σ

Given that z = -1.63, x = 23, and μ = 35:

-1.63 = (23 − 35) / σ

σ ≈ 7.36

You might be interested in

marysya [2.9K]

$168,356\approx170,000$

4 0

2 years ago

valkas [14]

Answer:

37.5 Units

Step-by-step explanation:

8 0

2 years ago

Orlov [11]

First you must know that is i∧2= -1

x∧3-4x∧2+4x-16 = x∧2 (x-4) + 4 (x-4) = (x-4) (x∧2+4) = (x-4) (x∧2-(-4)) =

= (x-4) (x∧2-(-1) *4) = (x-4) (x∧2- i∧2*2∧2) = (x-4) (x∧2-(2i)∧2) = (x-4) (x-2i) (x+2i)

Good luck!!!

5 0

2 years ago

Zanzabum

A and d are the answers

4 0

2 years ago

dlinn [17]

I would just assume <span>a) find the probability that the student guesses EXACTLY 4 correct.

</span>

8 0

2 years ago